Answer:
The <u>Acidophilic Microbial</u> Community has low diversity with microorganisms primarily in Leptospirillum groups II and III and from Ferroplasma types I and II.
Explanation:
An acidophilic microorganism or plant is one which grows best in acidic conditions.
They are also referred to as microorganisms which occur in acidic natural (solfataric fields, sulphuric pools) and man-made (eg. Acid mine drainage) environments.
Acidophilic Microbes otherwise known as Acidophiles are an ecologically and economically important group.
They possess networked cellular adaptations for regulating intracellular pH. Several extracellular enzymes from acidophilic microbes are known to be functional at much lower pH than that inside the cells.
Acid stable enzymes have applications in several industries such as starch, baking, fruit juice processing, animal feed and pharmaceuticals, and some of them have already been commercialized. Acidophiles are widely used in bio-leaching of metals from low grade ores
Recent studies show that acidophiles are currently being considered to be utilized in bio-conversion and bio-remediation, as well as in microbial fuel cells to generate electricity.
Acidophilic microbes of similar characteristics are classifed in groups for ease of study and identification.
Leptospirillum Group II and II as well as Ferroplasma types I and II are groups of acidophilic microorganisms within the Acidophillic Microbial community.
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These preferences may have been advantageous in our evolutionary history, when food was less reliably available
-from quizlet
Answer:
0.153
Explanation:
We know the up-thrust on the fish, U = weight of water displaced = weight of fish + weight of air in air sacs.
So ρVg = ρ'V'g + ρ'V"g where ρ = density of water = 1 g/cm³, V = volume of water displaced, g = acceleration due to gravity, ρ'= density of fish = 1.18 g/cm³, V' = initial volume of fish, ρ"= density of air = 0.0012 g/cm³ and V" = volume of expanded air sac.
ρVg = ρ'V'g + ρ"V"g
ρV = ρ'V'g + ρ"V"
Its new body volume = volume of water displaced, V = V' + V"
ρ(V' + V") = ρ'V' + ρ"V"
ρV' + ρV" = ρ'V' + ρ"V"
ρV' - ρ"V' = ρ'V" - ρV"
(ρ - ρ")V' = (ρ' - ρ)V"
V'/V" = (ρ - ρ")/(ρ' - ρ)
= (1 g/cm³ - 0.0012 g/cm³)/(1.18 g/cm³ - 1 g/cm³)
= (0.9988 g/cm³ ÷ 0.18 g/cm³)
V'/V" = 5.55
Since V = V' + V"
V' = V - V"
(V - V")/V" = 5.55
V/V" - V"/V" = 5.55
V/V" - 1 = 5.55
V/V" = 5.55 + 1
V/V" = 6.55
V"/V = 1/6.55
V"/V = 0.153
So, the fish must inflate its air sacs to 0.153 of its expanded body volume
Answer:
The correct answer is - decreases. direct.
Explanation:
Altitude is a distance measurement of distance in a vertical manner or how high something from the sea level. It helps in the height of the mountains and different places.
Air pressure and altitude are the two factors that are in direct relation as the air pressure decreases with the increase in altitude. the gases present in the higher elevations are fewer than the sea level.
