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3 years ago

Write 0.55% as a decimal and as a fraction

Mathematics

2 answers:

salantis [7]3 years ago

8 0

0.55%

= 55/100

= 11/20

Hope it helps

Ymorist [56]3 years ago

6 0

.5/10 the fraction cost

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(-55) +____ = -89<br> Find the missing

Mamont248 [21]

(-34) is the missing..

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3 years ago

Hello, I gotta turn it turn in this question today, help!!!!!!

Sladkaya [172]

Answer:

2 or -2

Step-by-step explanation:

If x² - 8x = -12

Step 1

We find x by solving

x² - 8x = -12

We equate to zero

x² - 8x + 12 = 0

We factorise

x² - 6x - 2x + 12 = 0

x(x - 6) -2(x - 6) = 0

(x - 6) (x - 2) = 0

x - 6 = 0, x = 6

x - 2 = 0, x = 2

x = 6 or 2

Step 2

What is x - 4?

When x = 6

= 6 - 4 = 2

When x = 2

= 2 - 4 = -2

Therefore, x - 4 = 2 or -2

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3 years ago

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Artemon [7]

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8 0

3 years ago

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elixir [45]

Answer:

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Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Limit definition for slope of the graph, equation of tangent line point for<br> f(x)=2x^2 at x=(-1)

Tems11 [23]

The slope of the tangent line to $f$ at $x=-1$ is given by the derivative of $f$ at that point:

$f'(-1)=\displaystyle\lim_{x\to-1}\frac{f(x)-f(-1)}{x-(-1)}=\lim_{x\to-1}\frac{2x^2-2}{x+1}$

Factorize the numerator:

$2x^2-2=2(x^2-1)=2(x-1)(x+1)$

We have $x$ approaching -1; in particular, this means $x\neq-1$ , so that

$\dfrac{2x^2-2}{x+1}=\dfrac{2(x-1)(x+1)}{x+1}=2(x-1)$

Then

$f'(-1)=\displaystyle\lim_{x\to-1}\frac{2x^2-2}{x+1}=\lim_{x\to-1}2(x-1)=2(-1-1)=-4$

and the tangent line's equation is

$y-f(-1)=f'(-1)(x-(-1))\implies y-4x-2$

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3 years ago