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GalinKa [24]
3 years ago
6

If 26.97 ÷ 6.3 is written in long division form as so that the divisor is written as a whole number, where should the decimal po

int be placed in the dividend?
Mathematics
1 answer:
Soloha48 [4]3 years ago
8 0
<h2>Answer:</h2>

The decimal point should be placed between digits 9 and 7 in the dividend. i.e the dividend becomes 269.7

<h2>Step-by-step explanation:</h2>

Dividend = 26.97       [numerator]

Divisor = 6.3               [denominator]

If 26.97 ÷ 6.3 is written in long division form so that the divisor is written as a whole number, we have the following;

(i)First convert the divisor to a whole number by multiplying by 10 i.e

6.3 x 10 = 63

(ii) Since the divisor (denominator) has been multiplied by 10, to make sure the division expression stays the same, we need to multiply the dividend(numerator) too by 10. i.e

26.97 x 10 = 269.7

(iii) The division expression then becomes;

269.7 ÷ 63

Therefore, the decimal point should be placed between digits 9 and 7 in the dividend.

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Step-by-step explanation:

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Putting values:

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\x=\frac{-(-12)\pm\sqrt{(-12)^2-4(1)(40)}}{2(1)}\\x=\frac{12\pm\sqrt{144-160}}{2}\\x=\frac{12\pm\sqrt{-16}}{2}\\We\,\,know\,\,\sqrt{-1}=i\\ x=\frac{12\pm4i}{2}\\ x=\frac{12+4i}{2}\,\,and\,\, x=\frac{12-4i}{2}\\ x=\frac{4(3+i)}{2}\,\,and\,\, x=\frac{4(3-i)}{2}\\x=2(3+i)\,\,and\,\,x=2(3-i)\\x=6+2i\,\,and\,\,x=6-2i

So, solving the equation x^2-12x+40=0 we get x=6+2i\,\,and\,\,x=6-2i

Keywords: Solving quadratic equation

Learn more about Solving quadratic equation at:

  • brainly.com/question/1414350
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#learnwithBrainly

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