Can some1 please help:(

A woman jogs for 2 km at 8 km/h and then walks for 2 km

Artemon [7]

Answer:

6 6/7 km/h

Step-by-step explanation:

The relations between speed, time, and distance are ...

time = distance/speed

speed = distance/time

__

So, to find the average speed, we need to know the total distance and the total time. The distances are given, but we need to compute the times.

time jogging = (2 km)/(8 km/h) = 1/4 h

time walking = (2 km)/(6 km/h) = 1/3 h

Then the woman's average speed is ...

average speed = (total distance)/(total time) = (2 km + 2 km)/(1/4 h + 1/3 h)

= (4 km)/(7/12 h) = 48/7 km/h

= 6 6/7 km/h

3 0

3 years ago

Cheryl, Rita, and four of their friends go to a movie and share a 48-ounce bag of popcorn equally and three 48-inch licorice lac

kvv77 [185]

You divide each total amount by the number of persons Popcorn: 48/6 = 8 Licorice: 3 X 48 = 144 144/6 = 24 So each person ate 8 ounces of popcorn and 24 inches of licorice laces

4 0

3 years ago

Determine which problem matches the given inequality.

sergey [27]

Answer:

There are less than 5 1/2 cups of sugar.

Step-by-step explanation:

E D G E N U I T Y

Have a good day! (◕ヮ◕ヽ)

8 0

3 years ago

Read 2 more answers

The width of a large, rectangular-shaped tree farm is 1.9 kilometers. The length of the farm is 4.4 kilometers. What are the bes

Vinvika [58]

Answer:

9 square kilometers

Step-by-step explanation:

Let's round the width to 2.0 kilometers, and round the length to 4.5 kilometers.

We know that area is length times width, so

A = lw

A = 2.0*4.5

A = 9.0 square kilometers

If we do this on the calculator, it's around 9.36 square kilometers, so our estimate was good.

6 0

3 years ago

35 POINTS AVAILABLE

aliina [53]

Answer:

Part 1) The length of each side of square AQUA is $3.54\ cm$

Part 2) The area of the shaded region is $(486\pi-648)\ units^{2}$

Step-by-step explanation:

Part 1)

step 1

Find the radius of the circle S

The area of the circle is equal to

$A=\pi r^{2}$

we have

$A=25\pi\ cm^{2}$

substitute in the formula and solve for r

$25\pi=\pi r^{2}$

simplify

$25=r^{2}$

$r=5\ cm$

step 2

Find the length of each side of square SQUA

In the square SQUA

we have that

SQ=QU=UA=AS

$SU=r=5\ cm$

Let

x------> the length side of the square

Applying the Pythagoras Theorem

$5^{2}=x^{2} +x^{2}$

$5^{2}=2x^{2}$

$x^{2}=\frac{25}{2}\\ \\x=\sqrt{\frac{25}{2}}\ cm\\ \\ x=3.54\ cm$

Part 2) we know that

The area of the shaded region is equal to the area of the larger circle minus the area of the square plus the area of the smaller circle

Find the area of the larger circle

The area of the circle is equal to

$A=\pi r^{2}$

we have

$r=AB=18\ units$

substitute in the formula

$A=\pi (18)^{2}=324\pi\ units^{2}$

step 2

Find the length of each side of square BCDE

we have that

$AB=18\ units$

The diagonal DB is equal to

$DB=(2)18=36\ units$

Let

x------> the length side of the square BCDE

Applying the Pythagoras Theorem

$36^{2}=x^{2} +x^{2}$

$1,296=2x^{2}$

$648=x^{2}$

$x=\sqrt{648}\ units$

step 3

Find the area of the square BCDE

The area of the square is

$A=(\sqrt{648})^{2}=648\ units^{2}$

step 4

Find the area of the smaller circle

The area of the circle is equal to

$A=\pi r^{2}$

we have

$r=(\sqrt{648})/2\ units$

substitute in the formula

$A=\pi ((\sqrt{648})/2)^{2}=162\pi\ units^{2}$

step 5

Find the area of the shaded region

$324\pi\ units^{2}-648\ units^{2}+162\pi\ units^{2}=(486\pi-648)\ units^{2}$

7 0

3 years ago