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vlabodo [156]
4 years ago
6

1. A figure has symmetry with respect to a point P if for every point Q of the figure a partner point Q' exists such that P is t

he of QQ’. 2. A figure has symmetry with respect to a plane X if for every point K of the figure a partner point K' exists such that X is the of KK’. 3. A figure has symmetry with respect to a line m if for every point P of the figure a partner point P' exists such that m is the of PP’.
Mathematics
2 answers:
suter [353]4 years ago
6 0

Answer:(5,15)

Step-by-step explanation:First I had to get a cordinate grid then i plotted point A then went 8 points up to get (5,15).

pochemuha4 years ago
6 0

Answer:

1. A figure has symmetry with respect to a point P if for every point Q of the figure a partner point Q' exists such that P is the <u>midpoint</u> of QQ’.

2. A figure has symmetry with respect to a plane X if for every point K of the figure a partner point K' exists such that X is the <u>perpendicular bisector</u> of KK’.

3. A figure has symmetry with respect to a line m if for every point P of the figure a partner point P' exists such that m is the <u>perpendicular bisector</u>  of PP’.

Step-by-step explanation

The  following options were missing: <em>perpendicular bisector or midpoint</em>

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<u>Alternative interior angles</u> are angles that are formed inside the two parallel lines, and the values are equal.

The <u>angle sum theorem</u> implies that the sum of interior angles of a triangle is 180°

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Step-by-step explanation:

<u>Given information:</u>

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Therefore, ∠EBC = 50°

\Large\boxed{x=50}

Hope this helps!! :)

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