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PSYCHO15rus [73]
2 years ago
7

PLZ HELP NEED ANSWER ASAP! A sports club rewards teams based on overall points earned in a season. The data for points are shown

in the table, where Low represents the fewest points scored and High represents the highest points scored by a single team member. Team Low High Range Mean Median IQR σ Team A 22 58 36 42.1 44 18.25 10.35 Team B 38 49 11 43.9 44.5 3.5 2.97 Team C 27 36 9 31.8 32 3.75 2.55 Part A: If the club wants to award the team that has the most consistent scoring among its team members, which team should it choose and why? Justify your answer mathematically. (5 points) Part B: If the club wants to award the team with the highest average score, which team should it choose and why? Justify your answer mathematically. (5 points)
Mathematics
1 answer:
uysha [10]2 years ago
4 0
<span>You are given the following data and in order to answer the questions below, base your analysis in the given data.

Team Low High Range Mean Median IQR σ
Team A 22 58 36 42.1 44 18.25 10.35
Team B 38 49 11 43.9 44.5 3.5 2.97
Team C 27 36 9 31.8 32 3.75 2.55

Part A: If the club wants to award the team that has the most consistent scoring among its team members, the team that should it choose is Team B because it has only lesser points if it scored low, at 38 and it has the next to the highest score among the three team, which is 49. Also, the range of their performance is 43.9, a much better score than 42.1 in Team A and 31.8 in Team C. 

Part B: If the club wants to award the team with the highest average score, </span>Team A because it has only lesser points if it scored low, at 22 and it has the highest score among the three team, which is 58. 
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Parallel / Perpendicular Practice
deff fn [24]

The slope and intercept form is the form of the straight line equation that includes the value of the slope of the line

  1. Neither
  2. ║
  3. Neither
  4. ⊥
  5. ║
  6. Neither
  7. Neither
  8. Neither

Reason:

The slope and intercept form is the form y = m·x + c

Where;

m = The slope

Two equations are parallel if their slopes are equal

Two equations are perpendicular if the relationship between their slopes, m₁, and m₂ are; m_1 = -\dfrac{1}{m_2}

1. The given equations are in the slope and intercept form

\ y = 3 \cdot x + 1

The slope, m₁ = 3

y = \dfrac{1}{3} \cdot x + 1

The slope, m₂ = \dfrac{1}{3}

Therefore, the equations are <u>neither</u> parallel or perpendicular

  • Neither

2. y = 5·x - 3

10·x - 2·y = 7

The second equation can be rewritten in the slope and intercept form as follows;

y = 5 \cdot x -\dfrac{7}{2}

Therefore, the two equations are <u>parallel</u>

  • ║

3. The given equations are;

-2·x - 4·y = -8

-2·x + 4·y = -8

The given equations in slope and intercept form are;

y = 2 -\dfrac{1}{2}  \cdot x

Slope, m₁ = -\dfrac{1}{2}

y = \dfrac{1}{2}  \cdot x - 2

Slope, m₂ = \dfrac{1}{2}

The slopes

Therefore, m₁ ≠ m₂

m_1 \neq -\dfrac{1}{m_2}

The lines are <u>Neither</u> parallel nor perpendicular

  • <u>Neither</u>

4. The given equations are;

2·y - x = 2

y = \dfrac{1}{2} \cdot   x +1

m₁ = \dfrac{1}{2}

y = -2·x + 4

m₂ = -2

Therefore;

m_1 \neq -\dfrac{1}{m_2}

Therefore, the lines are <u>perpendicular</u>

  • ⊥

5. The given equations are;

4·y = 3·x + 12

-3·x + 4·y = 2

Which gives;

First equation, y = \dfrac{3}{4} \cdot x + 3

Second equation, y = \dfrac{3}{4} \cdot x + \dfrac{1}{2}

Therefore, m₁ = m₂, the lines are <u>parallel</u>

  • ║

6. The given equations are;

8·x - 4·y = 16

Which gives; y = 2·x - 4

5·y - 10 = 3, therefore, y = \dfrac{13}{5}

Therefore, the two equations are <u>neither</u> parallel nor perpendicular

  • <u>Neither</u>

7. The equations are;

2·x + 6·y = -3

Which gives y = -\dfrac{1}{3} \cdot x - \dfrac{1}{2}

12·y = 4·x + 20

Which gives

y = \dfrac{1}{3} \cdot x + \dfrac{5}{3}

m₁ ≠ m₂

m_1 \neq -\dfrac{1}{m_2}

  • <u>Neither</u>

8. 2·x - 5·y = -3

Which gives; y = \dfrac{2}{5} \cdot x +\dfrac{3}{5}

5·x + 27 = 6

x = -\dfrac{21}{5}

  • Therefore, the slopes are not equal, or perpendicular, the correct option is <u>Neither</u>

Learn more here:

brainly.com/question/16732089

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3 years ago
The 3 sides of a triangle have lengths of (4x+3) cm, (2x+8) cm, and (3x-10) cm. What is the length of the shortest side if the p
galina1969 [7]

Answer:

The shortest sides is 3x-10

Step-by-step explanation:

This is because if you do the algebra which is 4x+3+2x+8+3x-10=136, x=15. Now that you have 15 you plug it into each sides x value. First, 4x+3= 4*15+3=63

Second, 2x+8=30+8=38

Lastly, 3x-10=45-10=35

So, as you can see here 35 is the lowest value which means the side (3x-10) is the shortest.

3 0
3 years ago
Which phase represents the algebraic expression
Charra [1.4K]
Answer:






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3 years ago
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Two piecewise functions are shown below. What is the value of
gizmo_the_mogwai [7]

Step-by-step explanation:

I am not sure what your problem here is.

you understand the inequality signs ?

anyway, to get

6×f(-2) + 3×g(1)

we can calculate every part of the expression separately, and then combine all the results into one final result.

f(-2)

we look at the definition.

into what category is -2 falling ? the one with x<-2, or the one with x>=-2 ?

is -2 < -2 ? no.

is -2 >= -2 ? yes, because -2 = -2. therefore, it is also >= -2.

so, we have to use

1/3 x³

for x = -2 that is

1/3 × (-2)³ = 1/3 × -8 = -8/3

g(1)

again, we look at the definition.

into what category is 1 falling ? the one with x > 2 ? or the one with x <= 1 ?

is 1 > 2 ? no.

is 1 <= 1 ? yes, because 1=1. therefore it is also <= 1.

so we have to use

2×|x - 1| + 3

for x = 1 we get

2×0 + 3 = 3

6×f(-2) = 6 × -8/3 = 2× -8 = -16

3×g(1) = 3× 3 = 9

and so in total we get

6×f(-2) + 3×g(1) = -16 + 9 = -7

3 0
1 year ago
Lesson 5: Lines and Triangles Geometry A Unit 4: Parallel and Perpendicular Lines
aev [14]
The Triangle Sum Theorem states that the sum of the angles of a triangle equal 180°. 
Therefore,
45° + 62° + k = 180
   107°      + k = 180
                   k  = 73°
The value of k is 73°
3 0
3 years ago
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