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PSYCHO15rus [73]
3 years ago
7

PLZ HELP NEED ANSWER ASAP! A sports club rewards teams based on overall points earned in a season. The data for points are shown

in the table, where Low represents the fewest points scored and High represents the highest points scored by a single team member. Team Low High Range Mean Median IQR σ Team A 22 58 36 42.1 44 18.25 10.35 Team B 38 49 11 43.9 44.5 3.5 2.97 Team C 27 36 9 31.8 32 3.75 2.55 Part A: If the club wants to award the team that has the most consistent scoring among its team members, which team should it choose and why? Justify your answer mathematically. (5 points) Part B: If the club wants to award the team with the highest average score, which team should it choose and why? Justify your answer mathematically. (5 points)
Mathematics
1 answer:
uysha [10]3 years ago
4 0
<span>You are given the following data and in order to answer the questions below, base your analysis in the given data.

Team Low High Range Mean Median IQR σ
Team A 22 58 36 42.1 44 18.25 10.35
Team B 38 49 11 43.9 44.5 3.5 2.97
Team C 27 36 9 31.8 32 3.75 2.55

Part A: If the club wants to award the team that has the most consistent scoring among its team members, the team that should it choose is Team B because it has only lesser points if it scored low, at 38 and it has the next to the highest score among the three team, which is 49. Also, the range of their performance is 43.9, a much better score than 42.1 in Team A and 31.8 in Team C. 

Part B: If the club wants to award the team with the highest average score, </span>Team A because it has only lesser points if it scored low, at 22 and it has the highest score among the three team, which is 58. 
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Complete question:

Assume that different groups of couples use a particular method of gender selection and each couple gives birth to one baby this mention is designed to increase the likelihood that each baby will be a girl, but assume that the method has no effect so the probability of a girl is 0.5. Assume that the group consists of 36 couples.

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p = 0.5

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