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3 years ago

Please help asap!!!

Mathematics

2 answers:

iren2701 [21]3 years ago

5 0

D I think because you have to multiply 5 with both y and w.

Anon25 [30]3 years ago

3 0

5y + 5w

factor out a 5

5(y+w)

Choice D

the 5 can go on either end of (y+w)

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What is the percent decrease if the original price is $582 and it went down 30%

Semenov [28]

Answer:

30%

Step-by-step explanation:

What is the percent decrease if the original price is $582 and it went down 30%

or decreased 30%

Check:

582 x 0.70 = 407.4

582-407.4=174.6

174.6/582= 0.3

5 0

3 years ago

M m m m basically what does x equal i guess i dont know for 3x+4

andrey2020 [161]

Answer:

<u>x = -4/3</u>

Step-by-step explanation:

3x + 4 = 0

3x = -4

<u>x = -4/3</u>

3 0

3 years ago

Read 2 more answers

On a farm the number of cows and the number of sheep are in the tatio 6:5 the number of sheep and the number of pigs are in the

Rzqust [24]

Answer:

There are 70 sheep in the farm.

Step-by-step explanation:

Consider the provided information.

Let c represents the cows, s represents the sheep and p represents the pigs.

The number of cows and the number of sheep are in the ratio 6:5.

$\dfrac{c}{s} =\dfrac{6}{5}$

$c =\dfrac{6s}{5}$

The number of sheep and the number of pigs are in the ratio 2:1.

$\dfrac{s}{p} =\dfrac{2}{1}$

$p =\dfrac{s}{2}$

The total number is 189.

$c+s+p=189$

Substitute the value of c and p in above.

$\dfrac{6s}{5}+s+\dfrac{s}{2}=189$

$\dfrac{12s+10s+5s}{10}=189$

$27s=1890$

$s=70$

Hence, there are 70 sheep in the farm.

8 0

3 years ago

PLEASE HELP!I'M NEWW

mixer [17]

Answer:

I think its 90°, since it l00ks like a right angle

5 0

3 years ago

The Friendly Sausage Factory (FSF) can produce hot dogs at a rate of 5,750 per day. FSF supplies hot dogs to local restaurants a

NARA [144]

Answer:

A) 22812 hotdogs per run

B) 75 runs/yr

C) 4 days in a run

Step-by-step explanation:

We are given;

Production rate;p = 5750 per day

Steady Usage rate;u = 270 per day

Setup cost of hotdog;S = $67

Annual carrying cost (H) = 47 cents = $0.47 per hot dog

No. of Production days; d = 297 days

A) Let's first find the annual demand given by the formula;

Annual demand;D = pd

D = 5750 × 297

D = 1707750 hot dogs/yr

Now, formula for optimal run size is given by;

Q_o = √[(2DS/H) × (p/(p - u))]

Plugging in the relevant values gives;

Q_o = √[(2 × 1707750 × 67/0.47) × (5750/(5650 - 270))]

Q_o =√520375454.7971209

Q_o = 22812 hotdogs per run

B) formula for Number of runs per year is given as;

No. of Runs = D/Q₀

Thus;

no. of runs = 1707750/22812

no. of runs ≈ 75 runs/yr

C) Length of a run is given by the formula;

Length = Q₀/p

Length = 22812/5750

Length ≈ 4 days in a run

6 0

3 years ago