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viva [34]
3 years ago
6

Evaluate (-3a+4b)32c-1 when a = 3, b = 1, and c = 4.

Mathematics
2 answers:
UNO [17]3 years ago
6 0

Answer:

-641.

Step-by-step explanation:

Nataly [62]3 years ago
5 0

<h2>( - 3a + 4b ) 32c - 1</h2>

<h3>( - 3 ( 3 ) + 4 ( 1 ) ) 32 ( 4 ) - 1</h3>

<h2>= 502</h2>

hope that helps:))

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If the product of two consecutive integers is 156 what type of equation do you create to solve this problem
zhenek [66]
I'm not sure, but I knew that 12×12=144 so I guessed that it was 12×13 and checked what that was and it was 156, so I guess and check probably
6 0
3 years ago
Read 2 more answers
Sklyer has 15 less than twice as many customers as when she started selling newspapers. She now has 155 customers. How many did
arlik [135]
155 = 2x -15
170 = 2x
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in general, what does the graph of an equation of the form y=a, where a is any real number, look like?
xeze [42]

Answer:

It will look like a horizontal line.  It would go through the y axis is a straight line through a.

Step-by-step explanation:

7 0
2 years ago
Drag the tiles to the correct boxes to complete the pairs.
olchik [2.2K]

Answer:

1)(2m^2-4m)/2(m-2) = m (fourth blank)

2)m^2-2m+1/m-1= m-1 (second blank)

3)m^2-3m+2/m^2-m= (m-2)/m (first blank)

4)m^2-m-2/m^2-1=(m-2)/(m-1)    (third blank)

Step-by-step explanation:

1)

(2m^2-4m)/2(m-2)

=[2m(m-2m)]/2(m-2)

= 2m/2

=m

2)

m^2-2m+1/m-1

= (m-1)^2/(m-1)

=(m-1)(m-1)/(m-1)

=(m-1)

3)

m^2-3m+2/m^2-m

=m^2-m-2m+2/m(m-1)

=m(m-1)-2(m-1)/m(m-1)

= (m-1)(m-2)/m(m-1)

=(m-2)/m

4)

m^2-m-2/m^2-1

=m^2+m-2m-2/(m+1)(m-1)

=m(m+1)-2(m+1)/(m+1)(m-1)

=(m+1)(m-2)/m+1)(m-1)

=(m-2)/(m-1) !

5 0
3 years ago
I will give brainly for the correct answer
MrRissso [65]

Answer:

c is the answer for the question

8 0
3 years ago
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