we know that
The measurement of the exterior angle is the semi-difference of the arcs which comprises
In this problem
∠FGH is the exterior angle
∠FGH=
∠FGH=
-----> equation A

--------> equation B
Substitute equation B in equation A
![100\°=(arc\ FEH-[360\°-arc\ FEH])](https://tex.z-dn.net/?f=100%5C%C2%B0%3D%28arc%5C%20FEH-%5B360%5C%C2%B0-arc%5C%20FEH%5D%29)



therefore
<u>The answer is</u>
The measure of arc FEH is equal to 
Answer:
43.3cm
Step-by-step explanation:
Circumference = PI * diameter.
Circumference = PI * 13.8
Circumference = 43.3cm
You're going to go to 50 on the y-axis and put a point there and then from 50 the slope needs to be a rise over run so go up 4 right 1:)
Answer:
1.75=b
Step-by-step explanation:
do the equation:
-2=3/4(5)+b
-2=-3.75+b
+3.75 to both sides
1.75=b