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Lerok [7]
4 years ago
8

Solve for q^2 equals 225

Mathematics
1 answer:
padilas [110]4 years ago
4 0
The answer to the question is 15
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A store sells cooking oil of two different brands in bottles of the same size. The table below and the equation each show the pr
Alexxandr [17]
Using the data, we can calculate the price per bottle for Brand A, which is:
24 / 2
= $12 per bottle

We also know that the slope of a line shows the rate of change, so the price per bottle for Brand B is $15. 

The difference per bottle is 15 - 12 = Brand B is cost $3 more per bottle
The difference for 9 bottles will be: 9 * 3 = $27.
7 0
3 years ago
Four more than the quotient of a number and 9 equals 2<br><br> Translate it to an equation
Georgia [21]
4(x÷9)=2

4 is multiplied to the (x÷9) to get your answer of 2
8 0
3 years ago
3. Which expression is equivalent to log532?
saul85 [17]

Answer: The Nth power xN of a number x was originally defined as x multiplied by itself, until there is a total of N identical factors. By means of various generalizations, the definition can be extended for any value of N that is any real number.

(2) The logarithm (to base 10) of any number x is defined as the power N such that

x = 10N

(3) Properties of logarithms:

(a) The logarithm of a product P.Q is the sum of the logarithms of the factors

log (PQ) = log P + log Q

(b) The logarithm of a quotient P / Q is the difference of the logarithms of the factors

log (P / Q) = log P – log Q

(c) The logarithm of a number P raised to power Q is Q.logP

log[PQ] = Q.logP

Step-by-step explanation:

8 0
3 years ago
The polynomial f(x) is written in factored form:
qaws [65]

Answer:

x = 6, x = -5, x = 9

if f(x)=(x-6)(x+5)(x-9)

Step-by-step explanation:

The zeros of a polynomial in factored form can be found by setting the polynomial equal to zero and then realizing if a product is zero, then at least one of it's factors is zero.

So we have the zero's are the x's that satisfy

(x-6)(x+5)(x-9)=0.

We just need to solve three equations:

x-6=0

           This can be solved by adding 6 on both sides:  x=6

x+5=0

         This can be solved by subtracting 5 on both sides: x=-5

x-9=0

         This can be solved by adding 9 on both sides: x=9

The solutions are in { 6,-5,9 }.

7 0
4 years ago
Read 2 more answers
Another question I need help with. I've got the part where it says to rewrite as a radical expression on my paper, but I'm havin
Alik [6]
\bf a^{\frac{ n}{ m}} \implies  \sqrt[ m]{a^ n} &#10;\qquad \qquad&#10;\sqrt[ m]{a^ n}\implies a^{\frac{ n}{ m}}\\\\&#10;-------------------------------\\\\&#10;32^{\frac{3}{5}}\implies \sqrt[5]{32^3}\qquad &#10;\begin{cases}&#10;32=2\cdot 2\cdot 2\cdot 2\cdot 2\\&#10;\qquad 2^5&#10;\end{cases}\implies \sqrt[5]{(2^5)^3}\implies \sqrt[5]{(2^3)^5}&#10;\\\\\\&#10;2^3\implies 8
4 0
4 years ago
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