To arrange numbers from least to greatest:
First write them down in decimal form. Now it will be easy to determine which value is greater than the other.
Arrange the decimal numbers from least to greatest.
Finally revert the decimal values to their fraction form having arranged them from one with least value to one with greatest value.
PART ;
......Circle A.................
Circumference - 2 pi r
25.12 = 2pi(4)
25.12 = 8i
Divide both sides by 8!!
3.14=pi
...Circle B.....................
Circumference = 2 pi r
9.42 = 2pi(3/2)
9.42 = 3pi
Divide both sides by 3!!!
3.14 = pi
PART B
.............Circle A...............
A=pi r ^2
50.24 = pi(4)^2
50.24=16pi
Divide both sides by 16!!!
3.14=pi
.............Circle B.............
A=pi r^2
7.065=pi(3/2)^2
7.065= 9pi/4
Divide both sides by 9/4!!!
3.14=pi
PART C
They used exactly 3.14 for the value of pi in CIRCLE A and B to get the circumference and the area :D
I hope this makes sense!!!
When I wrote 'pi', it was supposed to be the symbol for pi.
The area is 76 ft squared, and the perimeter is 43.1 ft. CORRECT ME IF IM WRONG BECAUSE I WAS SO BAD AT AREA/PERIMETER
Answer:
The length of EF is 5.29
Step-by-step explanation:
If BC = 12 then;
FB = 12 × sin65 = 10.876
BA = FB/(sin50) = 10.876/(sin50) = 14.2
BD = AB (Sides of isosceles triangle) = 14.2
∴ DF = BD + FB = 10.876 + 14.2 = 25.07
∠F C D = tan⁻¹(D F/F C) = tan⁻¹(25.07/(12×cos65)) = 78.6
∠F A D = tan⁻¹(D F/A F) = tan⁻¹(25.07/(14.2×cos50)) = 70
∴ ∠D = 180 - (78.6° + 70°) = 31.4°
AE = AD × sin31.4° = 2×AB×cos(70° - 50°) × sin31.4
∴ AE = 2×14.2×cos(20°) × sin31.4 = 13.92
EC = AC × cos78.6° = (AB×cos50 + BC×cos65)×cos78.6° = 2.815
Therefore, from cosine rule, a² = b² + c² - 2·b·c × cos(A)
Hence, we have;
EF² = EC² + FC² - 2 × EC × FC ×cos∠FCD (Cosine rule)
That is, EF² = 2.815² + (12×cos65)² - 2 × 2.815× (12×cos65) ×cos78.6°
EF² = 27.98
∴EF = √27.98 = 5.29.
Answer:
π/6 [37^(³/₂) − 1] ≈ 117.3187
Step-by-step explanation:
The surface area is:
S = ∫ 2π (x − 0) √(1 + (dx/dy)²) dy
0 ≤ x ≤ 3, so -4 ≤ y ≤ 5.
Find dx/dy.
y = 5 − x²
x² = 5 − y
x = √(5 − y)
dx/dy = ½ (5 − y)^(-½) (-1)
dx/dy = -½ (5 − y)^(-½)
(dx/dy)² = ¼ (5 − y)^(-1)
(dx/dy)² = 1 / (4 (5 − y))
Plug in:
S = ∫₋₄⁵ 2π x √(1 + 1 / (20 − 4y)) dy
S = ∫₋₄⁵ 2π √(5 − y) √(1 + 1 / (4 (5 − y))) dy
S = ∫₋₄⁵ 2π √((5 − y) + 1/4)) dy
S = ∫₋₄⁵ 2π √(5.25 − y) dy
If u = 5.25 − y, then du = -dy.
S = ∫ 2π √u (-du)
S = -2π ∫ √u du
S = -2π (⅔ u^(³/₂))
S = -4π/3 u^(³/₂)
Substitute back:
S = -4π/3 (5.25 − y)^(³/₂)
Evaluate between y=-4 and y=5.
S = [-4π/3 (5.25 − 5)^(³/₂)] − [-4π/3 (5.25 − -4)^(³/₂)]
S = -4π/3 (0.25)^(³/₂) + 4π/3 (9.25)^(³/₂)
S = π/6 [37^(³/₂) − 1]
S ≈ 117.3187
