Volume of a cylindrical container=πr²h
Container A:
πr²h=42 ounces of water.
Countainer B.
Volume of Container B=πr²(1.5 h)=1.5(πr²h)=1.5(42 ounces of water)=63 ounces of water.
Answer: the maximum amount of water that Container B can hold is 63 ounces of water.
Calculating the sum of 1 through 50: 50 x 51/2 = 25 x 51 = 1275.
Answer:
7(16-6)+3^3=7(16minus6) +3equivalent to 3equals
Distribute the 6 to 2x - 11
12x - 66 + 15 = 21
12x = 72
x = 6
