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dedylja [7]
3 years ago
8

Which tcp/udp port does the dns service use to communicate?

Computers and Technology
1 answer:
denis23 [38]3 years ago
7 0
Port 53

Man sometimes the answer minimum of 20 to explain is a bit unnecessary.
It's port 53 what else do you need to know?
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Erewrxdnnefwn q wedsvd
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hahahahahhahahahahhaha

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3 years ago
What does this say in morse code?
Furkat [3]

Answer:

That it is time for lunch?

Explanation:

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3 years ago
Read 2 more answers
In Python please.
SOVA2 [1]

Answer:

negatives = []

zeros = []

positives = []

while True:

   number = input("Enter a number: ")

   if number == "":

       break

   else:

       number = int(number)

       if number < 0:

           negatives.append(number)

       elif number == 0:

           zeros.append(number)

       else:

           positives.append(number)

for n in negatives:

   print(n)

for z in zeros:

   print(z)

for p in positives:

   print(p)

Explanation:

Initialize three lists to hold the numbers

Create a while loop that iterates until the user enters a blank line

Inside the loop:

If the number is smaller than 0, put it in the negatives list

If the number is 0, put it in the zeros list

Otherwise, put the number in the negatives list

When the while loop is done, create three for loops to print the numbers inside the lists

5 0
3 years ago
How many total numbers can be represented with an 8-bit binary (base-2) system?
ddd [48]

Answer:

256

Explanation:

4 0
3 years ago
) Consider a router that interconnects four subnets: Subnet 1, Subnet 2, Subnet 3 and Subnet 4. Suppose all of the interfaces in
erik [133]

Answer:

Check the explanation

Explanation:

223.1.17/24 indicates that out of 32-bits of IP address 24 bits have been assigned as subnet part and 8 bits for host id.

The binary representation of 223.1.17 is 11011111 00000001 00010001 00000000

Given that, subnet 1 has 63 interfaces. To represent 63 interfaces, we need 6 bits (64 = 26)

So its addresses can be from 223.1.17.0/26 to 223.1.17.62/26

Subnet 2 has 95 interfaces. 95 interfaces can be accommodated using 7 bits up to 127 host addresses can represented using 7 bits (127 = 27)

and hence, the addresses may be from 223.1.17.63/25 to 223.1.17.157/25

Subnet 3 has 16 interfaces. 4 bits are needed for 16 interfaces (16 = 24)

So the network addresses may range from 223.1.17.158/28 to 223.1.17.173/28

4 0
3 years ago
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