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Marrrta [24]
4 years ago
14

How many chapters are different from the other four types of quadrangles you have learned about

Mathematics
2 answers:
Bingel [31]4 years ago
7 0
Honestly that depends on where you are in this subjest so that isnt a proper question but ill guess 12 :)
svp [43]4 years ago
6 0
I'll geast 12 hi how is your day
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Which function equation is represented by the graph?
Murrr4er [49]

Answer:

I think the answer is D

Step-by-step explanation:

5 0
3 years ago
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Solve the inequality 5x7 < 2x - 1
Vanyuwa [196]

x is strictly less than 2 or x ∈ (-∞, 2)

Given: inequality 5x - 7 < 2x - 1

What are inequalities?

Inequalities are statements that are represented as comparison between two or more numbers or algebraic expressions.(strictly less, strictly great, greater, lesser)

Solving the given equation:

5x - 7 < 2x - 1

=> 5x - 7 - 2x < 2x - 1 - 2x

=> 3x - 7 < -1

=> 3x - 7 + 7 < -1 + 7

=> 3x < 6

=> x < 2

Therefore, x is strictly less than 2.

Hence x ∈ (-∞, 2)

The number line is attached below.                      

Know more about "inequalities" here: brainly.com/question/20383699

#SPJ9

Disclaimer: The given question is incomplete. The complete question is given below.

Solve the inequality 5x - 7 < 2x - 1

On the number line, represent the solution

(number line -5 to 5)​

5 0
2 years ago
5. Which description below describes<br>the equation. ​
Ymorist [56]
A. The number of mugs that fit four to a box
5 0
3 years ago
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Recall that m(t) = (1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500g sample of phosphorus-32 decays
katrin2010 [14]

The question is incomplete, here is the complete question:

Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.

<u>Answer:</u> The half life of the sample of phosphorus-32 is 14.28days^{-1}

<u>Step-by-step explanation:</u>

The equation used to calculate the half life of the sample is given as:

m(t)=m_o(1/2)^{t/h}

where,

m(t) =  amount of sample after time 't' = 356 g

m_o = initial amount of the sample = 500 g

t = time period = 7 days

h = half life of the sample = ?

Putting values in above equation, we get:

356=500\times (\frac{1}{2})^{7/h}\\\\h=14.28days^{-1}

Hence, the half life of the sample of phosphorus-32 is 14.28days^{-1}

7 0
4 years ago
Solve<br>(10) x 2 - (-7)^2​
erik [133]

Answer:

-39

Step-by-step explanation:

20-49

=49-20 but negative

=-39

5 0
4 years ago
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