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strojnjashka [21]
4 years ago
9

Will mark brainliest

Mathematics
2 answers:
Anni [7]4 years ago
6 0

Answer:

1.

Anya could find out her volume by multiplying 1.5*1.5*4 and then subracting that from 11*8.5.

Terrence could find out his volume by multiplying 3*3*4 and then subtracting that from 11*8.5

Anya's suggestion would maker a larger volume.

There can be 2 different volumes because someone might cut out more than the other person.

2.

I think there's something missing from this question.

kondor19780726 [428]4 years ago
6 0

Answer:

1. Anya's suggestion

2. Length is always positive

Step-by-step explanation:

Volume = length × width × height

1.

Volumes:

Anya's approach

1.5 is the height of the box

Since 2 squares are cut, the dimensions of the base reduce be 2×1.5 = 3

Volume = (11 - 3) × (8.5 - 3) × 1.5

= 55 in³

Terrence's approach

3 is the height of the box

Since 2 squares are cut, the dimensions of the base reduce be 2×3 = 6

Volume = (11 - 6) × (8.5 - 6) × 3

= 37.5 in³

2.

Dimensions of the base are:

(8.5-2x) × (11 - 2x)

Since length cannot be negative:

x > 0

8.5 - 2x > 0

2x < 8.5

x < 4.25

11 - 2x > 0

x < 5.5

The set of values of x which satisfies all is:

0 < x < 4.25

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Vladimir [108]

Answer:

1) 30

2) 40

Step-by-step explanation:

1) Nick will have finished 30 assignments in 6 hours because he can complete 5 assignments per hour and 6*5= 30.

2) Nick will have finished 40 assignments in 8 hours because he can complete 5 assignments per hour and 8*5= 40.

hope this helps!!

3 0
3 years ago
Read 2 more answers
In triangle △ABC, ∠ABC=90°, BH is an altitude. Find the missing lengths. AB=9, and AC=12, find HC.
pickupchik [31]

Answer:

Step-by-step explanation:

It is given that in △ABC, ∠ABC=90°, BH is an altitude and AB=9 and AC=12, thus using the Pythagoras theorem in △ABC, we get

(AC)^{2}=(AB)^{2}+(BC)^{2}

(12)^{2}=(9)^2+(BC)^2

144=81+(BC)^2

(BC)^2=63

BC=\sqrt{63}

Now, From ΔABC and ΔHBC, we have

∠ABC=∠BHC(each90)

∠ACB=∠HCB (Common)

By AA similarity, ΔABC is similar to ΔHBC.

Thus, using the similarity condition, we get

\frac{HC}{BC}=\frac{BC}{AC}

\frac{HC}{\sqrt{63}}=\frac{\sqrt{63}}{12}

HC=\frac{63}{12}=\frac{21}{4}

7 0
3 years ago
Solve the math problem
fredd [130]

Answer:

x=p

y=6

hope it helped u ☺️☺️☺️

7 0
3 years ago
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Determine if each proportion on the left is True or False. Answer options on the right side may be used more than once.
tangare [24]
28/16=14/8 TRUE
3/5=9/15 TRUE
4/32=10/78 FALSE
3/4=12/16 TRUE
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4 years ago
Help no links please please hurry make sure it’s correct
Sauron [17]
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tuesday: 6 hours
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saturday: 4 hours

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total hours:
6+3+4= 13 hours

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3 years ago
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