Short answer: I don't know, but that doesn't mean I can't give you something that you can decide for yourself.
y = 4*2^(2n - 2) is the pattern.
Go for broke. Try n = 4. You should get 256. Let's try it.
y = 4 * 2^(2*4 - 2)
y = 4 * 2^(8 - 2)
y = 4 * 2^6
y = 4 * 64
y = 256 yup it works.
The other end is just as important. Suppose n = 1
Then y = 4 * 2^(2*1 - 2) = 4 * 2^0 = 4*1 = 4 Both work.
If this formula is correct, we can abbreviate it to make your task easier.
y = 4 * 2^(2n - 2)
y = 2^2 * 2^(2n - 2)
y = 2^(2n - 2 + 2)
y = 2^(2n) Now try the two end points again.
n = 4
y = 2^(2*4)
y = 2^8
y = 256
n = 1
y = 2^(2*1)
y = 2^2
y = 4 which again checks.
so y = 2^(2n) I think is an exponential function.
Sorry my explanation is so long.
Answer:
If the gift card is $30 the remaining change is 3 dollars
Answer:
Step-by-step explanation:
For 
, there are two possible cases:
Solving for both cases, we get:
Answer:
The number of calculators is 4871
Step-by-step explanation:
If we integrate dx/dt we get x, which is the number of calculators. To find the number of calculators between the beginning of third week to the end of fourth week (the beginning of fifth week), this integration must be evaluated at t between 3 and 5.
the result of the integration is:
to be evaluated between 3 and 5, which is:
Y=(1/3)*x is the correct answer.
1/3 of -3 is -1
1/3 of 0 is 0
1/3 of 6 is 2
