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Alika [10]
3 years ago
8

PLEASE ANSWER ASAP

Mathematics
2 answers:
Oxana [17]3 years ago
6 0
The relationship is that cos 7pi/6 and cos 5pi/6 both are cosines of angles that have a reference angle of pi/6. cos 7pi/6 = cos 5pi/6 = -√3/2
hjlf3 years ago
5 0
It is known
 \dfrac{\pi}{6} =30^{\circ} and 
 \cos \dfrac{\pi}{6}= \dfrac{ \sqrt{3} }{2} (if you want to determine cosine of 30° you should draw the perpendicular line to the x-axis and find the point of intersection, the value of x-coordinate is the cosine of 30°).

The angle \dfrac{5\pi}{6} =150^{\circ} and
\cos \dfrac{5\pi}{6}=- \dfrac{ \sqrt{3} }{2} (see image).
The angle \dfrac{7\pi}{6} =210^{\circ} and

\cos \dfrac{7\pi}{6}=- \dfrac{ \sqrt{3} }{2} (see image).


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Determine which postulate can be used to prove that the triangles are congruent. If it is not possible to prove congruence, writ
irakobra [83]

Answer:

The triangles are congruent by

SSS

Step-by-step explanation:

Given:

First Label the Diagram:

AB ≅ CD

AD ≅ BC

To Prove:

Δ ABC ≅ Δ CDA

Proof:

In  Δ ABC and Δ CDA

AB ≅ CD     ....……….{Given}

BC ≅ DA     …………..{Given}

AC ≅ AC     ……….{Reflexive Property}

Δ ABC ≅ Δ CDA  ….{ By Side-Side-Side test}

8 0
3 years ago
Please help! ive been stuck on this for so long and i just keep getting frustrated can someone help walkme through this?
bagirrra123 [75]

For firework launched from height 100ft with initial velocity 150ft/sec, equation made is correct

(a) equation will be h(t) = -16t^2+150t+100

(b) Now we have to see when it will land. At land or ground level height h will be equal to 0. So simply plug 0 in h place in equation made in part (a)

0 = -16t^2 + 150t + 100

Now we have to solve this quadratic. We will use quadratic formula method to solve this equation.

t = \frac{-b \pm  \sqrt{b^2-4ac}}{2a}

a = -16, b = 150, c = 100.

Plugging these values in quadratic formula we get

t = \frac{-150 \pm  \sqrt{150^2-4(-16)(100)}}{2(-16)}

t = \frac{-150 \pm  \sqrt{22500+6400}}{-32}

t = \frac{-150 \pm  \sqrt{28900}}{-32}

t = \frac{-150+170}{-32}  = \frac{20}{-32} = -0.625

time cannot be negative so we will drop this answer

then t = \frac{-150-170}{-32}  = \frac{-320}{-32} = 10

So 10 seconds is the answer for this

(c) To make table simply plug various value for t like t =0, 2, 4, 6, 8 till 10. Plug values in equation mad in part (a) and find h value for each t as shown

For t =0 seconds, h = -16(0)^2+150(0)+100 = 100 feet

For t =2 seconds, h = -16(2)^2+150(2)+100 =336 feet

For t =4 seconds, h = -16(4)^2+150(4)+100 = 444 feet

For t =6 seconds, h = -16(6)^2+150(6)+100 = 424 feet

For t =8 seconds,h = -16(8)^2+150(8)+100 = 276 feet

For t =10 seconds, h = -16(10)^2+150(10)+100 = 0 feet

(d) Axis of symmetry is given by formula

x = \frac{-b}{2a}

t = \frac{-150}{2(-16)} =\frac{-150}{-32} = 4.6875

t = 4.6875 is axis of symmetry line

(e) x-coordinate of vertex is again given by formula

x = \frac{-b}{2a}

so t = 4.6875

then to find y coordinate we will plug this value of t as 4.6875 in equation made in part (a)

For t =4.6875, h = -16(4.6875)^2+150(4.6875)+100 = 451.563

so vertex is at (4.6875, 451.563)

(f) As the firework is launched so in starting time is t=0, we cannot have time before t=0 (negative values) practically. Also we cannnot have firework going down into the ground so we cannot have h value negative physically.

6 0
3 years ago
Trình bày khái niệm và cách giải phương trình bậc nhất 1 ẩn, hệ phương trình bậc nhất 2 ẩn
AysviL [449]
English please.......,.
8 0
3 years ago
How do I solve without s calculator?
baherus [9]
You could solve it ( without a graph) in 2 easy ways :

1 use the equation that you have written in pencil and solve for y

y=3=-x+4
y=-x +1

Or you could use the point slop form after you find the y intercept y=mx+b


-3=4(-1)+b
b= 1

So the answer would be y= -x +1


Hope this help of it does feel free to give the brainliest

5 0
3 years ago
What is the answer to 8(6+4×)=-176
taurus [48]

Answer:

Step-by-step explanation:

48+32x=-176

32x=224

x=7

3 0
3 years ago
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