In hamsters black coat color (b) is dominant to white coat color (b). a heterozygous black hamster, is mated with a heterozygous
1 answer:
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Answer: In this type of cross between MmDdPp and mmddpp, the phenotypic ratios in the eight possible phenotypes are as follow; a. solid, normal, smooth = 1:8
b. solid, normal, peach = 1:8
c. solid, dwarf, smooth = 1:8
d. solid, dwarf, peach = 1:8
e. mottled, normal, smooth = 1:8
f. mottled, normal, peach = 1:8
g. mottled, dwarf, smooth = 1:8
h. mottled, dwarf, peach = 1:8
Explanation: The number of gametes that can be formed from a particular genotype is given as 2^n where n is the number of heterozygous loci. In the genotype MmDdPp, n = 3. Therefore, 8 gametes can be formed.
In genotype mmddpp, n = 0. Therefore, only one type of gamete can be formed.
Crossing the two genotype (MmDdPp and mmddpp) as shown in the attached image, 8 possible offsprings can be achieved. Phenotypes of these offspring had been stated earlier. The phenotypic frequency of each of these offspring is one out of eight (⅛).
Answer:
The t-test
Explanation:
<em>The researcher should use a t-test to compare the two means and check if they are significantly different from each other.</em>
In using the t-test, both null (H0) and alternate (H1) hypothesis are made such that:
- H0: n1 = n2
- H1: n1≠ n2
Thereafter, the value of t is calculated and compared to its critical value on the table. The formula for calculating the t goes thus:
where, Y1 = mean of population 1, Y2 = mean of population 2, S1 = variance of population 1, S2 = variance of population 2, n1 = number of individuals in population 1 and s2 = number of individuals in population 2.
<em>At the end of the day, if the calculated t value is more than the critical value of t, the H0 is rejected and it shows that the two means are significantly different. Otherwise, the H0 is accepted and this shows that there is not significant difference between the mean of population 1 and that of 2.</em>