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Sonbull [250]
3 years ago
13

I will mark as brainiest for correct answer! Please help me! Thank you

Mathematics
1 answer:
Dmitrij [34]3 years ago
3 0
For the division part:
\frac{5-4}{4-3 }= \frac{1}{1 }=1

But I think your question differs than this..

Am I right?

as your options do not include 1
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HELP MEH PLZZZZZZZZZZ
tresset_1 [31]
Answer: y= -1/5x + 3
15y= -3x + 45
y= -3/15x + 3
y= -1/5x + 3
5 0
3 years ago
Read 2 more answers
The U.S Olympic Team has long distance runners who run a 10,000 meter race. If a runner was to run 50 races, how many centimeter
Ede4ka [16]
There are 100 centimeters in 1 meter. So to start with you must multiply 10000 by 100 to determine the number of centimeters in each race. This answer will be 1000000. Then to determine the number of centimeters in fifty races, you must multiply 1000000 by 50. This answer is 50000000. Then you must put it in scientific notation. 

To do this you must move the decimal place over to the left until there is only one, nonzero number in front of it. Because you will move it to the left, your exponent will be positive. Therefore, your answer will be B.
6 0
3 years ago
Any one know the answer for this question??????
Romashka [77]

Answer:

C) y > 0

Step-by-step explanation:

I graphed it

7 0
2 years ago
Which expression is equivalent to 4 square root 6 divided by 3 root 2?
saw5 [17]

Answer:

\sqrt[12]{55296}/2

Step-by-step explanation:

\sqrt[4]{6}/\sqrt[3]{2}=1.2422

\sqrt[12]{27}/2=0.66 <-- not matching with the top expression.

\sqrt[4]{24}/2=1.11<--not matching with the top expression.

\sqrt[12]{55296}/2=1.2422<-- matches!!

\sqrt[12]{177147}/3=0.91<-- not matching with the top expression.

5 0
3 years ago
Describe the possible values for x and y when ∣x − y ∣ &gt; 0. What does it mean when ∣x − y ∣ = 0? Can ∣x − y ∣ &lt; 0? Explain
Vilka [71]
The possible values for | x-y | > 0 is any number above 0. x must be greater than y. When | x-y | = 0, That means that x and y are equal to each other. | x-y | can not be less than 0, but it can equal 0.

Hope that this helped!
4 0
3 years ago
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