The answer would be $24.55 per oz of gold alloy so rounded up would be $25
G ( x ) = 2 - ( x - 7 )²
g ( x ) = 2 - ( x² - 14 x + 49 )
g ( x ) = 2 - x² + 14 x - 49
g ( x ) = - x² + 14 x - 47
The maximum of the function is at:
x= - b / 2 a
x = - 14 / ( - 2 ) = 7
Therefore the function is increasing form x ∈ ( - ∞, 7 ) and decreasing for x ∈ ( 7, +∞ ).
Answer:
C. increasing, x < 7; decreasing x > 7.
Answer:
8.62
Step-by-step explanation:
a squared + b squared = c squared
15 squared + b squared = 17.3 squared
225 + b squared = 299.29
b squared = 74.29
b = 8.619
Answer:
Cost of one roll of plain wrapping: ![\$5](https://tex.z-dn.net/?f=%5C%245)
Cost of one roll of holiday wrapping paper: ![\$19](https://tex.z-dn.net/?f=%5C%2419)
Step-by-step explanation:
Let be "p" the cost in dollars of one roll of plain wrapping paper and "h" the cost in dollars of one roll of holiday wrapping paper.
Based on the information given, we can set up this system of equations:
![\left \{ {{5p+13h=272} \atop {11p+16h=359}} \right.](https://tex.z-dn.net/?f=%5Cleft%20%5C%7B%20%7B%7B5p%2B13h%3D272%7D%20%5Catop%20%7B11p%2B16h%3D359%7D%7D%20%5Cright.)
In order to solve it, we can use the Substitution method. The steps are:
1. Solve for "p" from the first equation:
![5p+13h=272\\\\5p=272-13h\\\\p=\frac{272-13h}{5}](https://tex.z-dn.net/?f=5p%2B13h%3D272%5C%5C%5C%5C5p%3D272-13h%5C%5C%5C%5Cp%3D%5Cfrac%7B272-13h%7D%7B5%7D)
2. Substitute the above into the second equation and solve for "h":
3. Substitute the value of "h" into
:
![p=\frac{272-13(19)}{5}\\\\p=5](https://tex.z-dn.net/?f=p%3D%5Cfrac%7B272-13%2819%29%7D%7B5%7D%5C%5C%5C%5Cp%3D5)