Answer:
2 unit/time²
Step-by-step explanation:
Given the equation:
v(t) =t^2-3t
At interval ; 1, 4
V(1) = 1^2 - 3(1)
V(1) = 1 - 3
V(1) = - 2
At t = 4
V(4) = 4^2 - 3(4)
V(4) = 16 - 12
V(4) = 4
Average acceleration : (final - Initial Velocity) / change in time
Average acceleration = (4 - (-2)) ÷ (4 - 1)
Average acceleration = (4 + 2) / 3
Average acceleration = 6 /3
Average acceleration = 2
Answer:
y = 2x + 14
Step-by-step explanation:
Hope this helps!!!
First, you have to find the slope by using
In other words,
The slope is 2.
Then you plug the rest into point-slope form (you can use either of the points, I used the first one)
Remember that m is the slope.
Distribute the slope to the parenthesis
Isolate the y variable
Standard algorithm i think
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Line joining (-3, -1) and (1/2, 2)
Point point form for a line is
(c-a)(y-b) = (d-b)(x-a)
(1/2 - - 3)(y - -1) = (2 - -1)(x - -3)
(7/2)(y+1)=3(x+3)
7(y+1)=6(x+3)
7 - 6(3) = 6x - 7y
6x - 7y = -11
Answer: second choice, 6x - 7y = -11
