we know that
Area of the circle is equal to

where
r is the radius
in this problem



therefore
the answer is the option
d. 113.04 sq. in.
Since he descended 12 meters, we subtract this from the overall height of Mount Ka'ala, so then we are only calculating how high ABOVE the sea level it is.
1232 - 12 = 1220
The height of Mount Ka'ala is therefore 1,220 meters.
To calculate how much a fifth of Mount Ka'ala is (since the ranger station is 2/5's up), we would divide this number by 5
1220 ÷ 5 = 244
Since ONE fifth of the height is 244 meters, TWO fifths would be double that amount.
244 x 2 = 488
488 meters.
The ranger station is 488m above sea level.
Answer:
We can have two cases.
A quadratic function where the leading coefficient is larger than zero, in this case the arms of the graph will open up, and it will continue forever, so the maximum in this case is infinite.
A quadratic function where the leading coefficient is negative. In this case the arms of the graph will open down, then the maximum of the quadratic function coincides with the vertex of the function.
Where for a generic function:
y(x) = a*x^2 + b*x + c
The vertex is at:
x = -a/2b
and the maximum value is:
y(-a/2b)
The slope is either 5/2 or 2/5 and the y intercept is 3