Question

Find the LCM of x2 + x,x2-1,x2-x

Answer 1

Answer:

$first \: \\ x {}^{2} + x \\ = x(x + 1) \\ \\ second \\ {x}^{2} - 1 \\ = (x) {}^{2} - (1) { }^{2} \\ = (x + 1)(x - 1) \\ \\ third \\ x {}^{2} - x \\ = x(x - 1) \\ \\ therefore \: \: lcm = x(x + 1)(x - 1)$

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