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Vikki [24]
3 years ago
13

what best describes the number 5 right prime composite neither prime nor composite or both prime in composite

Mathematics
2 answers:
faltersainse [42]3 years ago
8 0
I think, 5 maybe?...
IrinaVladis [17]3 years ago
4 0
Im like 99.9999 percent sure its 5
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I need to find domain and range for this piecewise function.
dolphi86 [110]

Answer:

a) Domain is from [-3,3] U [4,0)

b)  Range is From (-2,2]

Step-by-step explanation:

a) To find the domain look at the x-axis where you find out that the it starts at -3 with dot( included) and ends till 3 and 4 included till 5 which is hole and not included.

b) To find the range look at the y-axis where you start from bottom -2 not included till 2 which is included.

6 0
3 years ago
What is the inverse of the function g() = 2/5 x + 3?​
Archy [21]

Answer:

5/2(x-3)​

Step-by-step explanation:

g(x) = 2/5 x + 3

y = 2/5x +3

Exchange x and y

x = 2/5y +3

Solve for y

Subtract 3 from each side

x-3 = 2/5y +3-3

x -3 = 2/5y

Multiply each side by 5/2

5/2(x-3) = 5/2(2/5)y

5/2(x-3) = y

The inverse is 5/2(x-3)​

8 0
3 years ago
Helppppppppppppppppppppp
anygoal [31]

Answer:

3 bags

Step-by-step explanation:

Even though she will have extra she still will need 3 bags to get 12.

4 0
3 years ago
Read 2 more answers
Graph the image of B (-3,-8) after a reflection over x axis
azamat
It going to be (-3,8)
4 0
3 years ago
A friend of mine is giving a dinner party. His current wine supply includes 8 bottles of zinfandel, 9 of merlot, and 11 of caber
Goshia [24]

Answer:

A friend of mine is giving a dinner party. His current wine supply includes 8 bottles of zinfandel, 9 of merlot, and 11 of cabernet (he only drinks red wine), all from different wineries.

(a) If he wants to serve 3 bottles of zinfandel and serving order is important, how many ways are there to do this?

8 * 7 * 6 = 8! / (8 - 3)! = 336

(b) If 6 bottles of wine are to be randomly selected from the 28 for serving, how many ways are there to do this?

28 * 27 * 26 * 25 * 24 * 23 / 6! = 28! / (6! * (28 - 6)!) = 376740

(c) If 6 bottles are randomly selected, how many ways are there to obtain two bottles of each variety?

8 * 7 / 2! * 9 * 8 / 2! * 11 * 10 / 2! = 55440

(d) If 6 bottles are randomly selected, what is the probability that this results in two bottles of each variety being chosen? (Round your answer to three decimal places.)

55440 / 376740 = 0.147

(e) If 6 bottles are randomly selected, what is the probability that all of them are the same variety? (Round your answer to three decimal places.)

8! / (6! * (8 - 6)!) + 9! / (6! * (9 - 6)!) + 11! / (6! * (11 - 6)!) = 574

574 / 376740 = 0.00152

8 0
4 years ago
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