Answer:
(A) It prevents electron flow from the iron-sulfur centers in complex 1 to the ubiquinone. Due to reduction in electron transfer rate, there is a decrease in the production of ATP which is dangerous for some insects and fish over time.
(B) It also prevents electron flow from cytochrome b to cytochrome c1 at the complex III which leads to QH2 accumulation. If oxidized Q is not present, these is alteration of electron flow and the production of ATP is altered.
(C) Rotenone only prevent electron transfer into the chain at Complex 1 but it does not affect electron transfer at Complex II. Although there is slow ETC, it does not stop completely. However, Antimycin A prevents the oxidation of QH2, the final electron acceptor crom complex I and complex II. Thereby, stopping the production of both ETC and ATP. It can be concluded that antimycin A is a more potent poison.
Explanation:
Rotenone prevents electron flow from the iron-sulfur centers in complex 1 to the ubiquinone. Due to a reduction in electron transfer rate, there is a decrease in the production of ATP which is dangerous for some insects and fish over time. Antimycin A also prevents electron flow from cytochrome b to cytochrome c1 at the complex III which leads to QH2 accumulation. If oxidized Q is not present, there is an alteration of electron flow and the production of ATP is altered. Antimycin A is more potent than rotenone.
Answer: The answer is Part F. Hope this helps :)
Explanation:
Answer:
So when the first animals moved onto land, they had to trade their fins for limbs, and their gills for lungs, the better to adapt to their new terrestrial environment
Explanation:
To form ammonia, we can react 2 molecules of N₂ with 6 molecules of H₂. Once the reaction has completed, the total molecules of each gas will be: 1 molecule of nitrogen, 3 molecules of hydrogen, and 4 molecules of ammonia.
<h3>How to predict the total molecules of reactants and products?</h3>
The formation reaction of ammonia needs one molecule of nitrogen and 3 molecules of hydrogen. The reaction is as shown in the equation below:
N2(g) + 3H2(g) --> 2NH3(g)
2N2(g) + 6H2(g) --> 4NH3(g)
They will form a new product as four molecules of NH₃. Speaking in the present time after the reaction has completed, half of the reactants (N₂ and 3H₂) are gone to form the ammonia. Hence, the correct answer is: 1 N₂, 3 H₂, and 4 NH₃.
This question seems incomplete. The complete query is as follows:
"We are reacting two molecules of nitrogen gas with six molecules of hydrogen gas to form ammonia, NH₃. How many molecules of each type of gas will be present once the reaction has completed?"
Learn more about the coefficients of a chemical reaction here brainly.com/question/28909749
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Answer:
<u><em>A diploid cell becomes haploid during Meiosis I and is completed after Telephase I. These homologous chromosomes (from mom & dad, all duplicated) pair up during prophase I forming tetrads. The pairs of homologs line up on the metaphase plate during metaphase I.</em></u>
Explanation:
