All categories

3 years ago

Simplify -19 + 13 + (-22)

Mathematics

2 answers:

Fudgin [204]3 years ago

6 0

19+13= 32 32/22 divide both by 2 and the answer is 15/11

Rudik [331]3 years ago

3 0

$-19+13+(-22)=-19+13-22=13-(19+22)=13-41=\boxed{-28}$

You might be interested in

Mark the statement either true (in all cases) or false (for at least one example). If false, construct a specific example to sho

LUCKY_DIMON [66]

Answer with Step-by-step explanation:

We are given that $v_1,v_2,..,v_4$ are in $R^4$ and $v_1,v_2,v_3$ is linearly dependent then {v_1,v_2,v_3,v_4}[/tex] is also linearly dependent.

We have to find that given statement is true or false.

Dependent vectors:Dependent vectors are those vectors in which atleast one vector is a linear combination of other given vectors.

Or If we have vectors $x_1,x_2,....x_n$

Then their linear combination

$a_1x_1+a_2x_2+.....+a_nx_n=0$

There exist at least one scalar which is not zero.

If $v_1,v_2,v_3$ are dependent vectors then

$a_1v_1+a_2v_2+a_3v_3=0$ for scalars $a_1,a_2,a_3$

Then , by definition of dependent vectors

There exist a vector which is not equal to zero

If vector $v_3$ is a linear combination of $v_1\;and \;v_2$ , So at least one of vectors in the set is a linear combination of others and the set is linearly dependent.

Hence, by definition of dependent vectors

{ $v_1,v_2,v_3,v_4$ } is linearly dependent.

Option B is true.

8 0

3 years ago

The base of a rectangular prism has dimensions of 3 feet by 4 feet.

Ksju [112]

I'm assuming it is asking for surface area.

SA = 2(lw) + 2(hw) + 2(lh)
SA = 2(3*4) + 2(4*8) + 2(3*8)
SA = 2(12) + 2(32) + 2(24)
SA = 24 + 64 + 48
SA = 136 square feet

3 0

3 years ago

A sample of 1000 college students at NC State University were randomly selected for a survey. Among the survey participants, 102

cupoosta [38]

Answer:

The upper endpoint of the 99% confidence interval for population proportion is 0.13.

Step-by-step explanation:

The confidence interval for population proportion is:

$CI=\hat p\pm z_{\alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

Given:

n = 1000

$\hat p$ = 0.102

$z_{\alpha /2}=z_{0.01/2}=z_{0.005}=2.58$

*Use the standard normal table for the critical value.

Compute the 99% confidence interval for population proportion as follows:

$CI=\hat p\pm z_{\alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n}}\\=0.102\pm 2.58\times\sqrt{\frac{0.102(1-0.102)}{1000}}\\=0.102\pm0.0248\\=(0.0772, 0.1268)\\\approx (0.08, 0.13)$