Simplify -19 + 13 + (-22)
2 answers:
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<h3>Answer:</h3>
In this question, we're trying to find the probability of it being cloudy and raining.
In this case, we know that:
- Probability of it being cloudy is 30%
- Probability of it raining is 25% (this is necessarily not needed)
- If it's cloud, the probability of it raining is 45%
With the information above, we can find the probability.
We know that from a 100% scale, the chance of it being cloudy is 30%.
We know that if it's cloudy, the chances of raining is 45%
To find the probability of it being cloudy and raining, we would multiply 0.3 (30%) by 0.45 (45%)
Solve:
Your answer would be C). 13.5%
<h3>I hope this helped you out.</h3><h3>Good luck on your academics.</h3><h3>Have a fantastic day!</h3>Answer:
1.7 × 10⁻⁴
Step-by-step explanation:
The question relates to a two sample z-test for the comparison between the means of the two samples
The null hypothesis is H₀: μ₁ ≤ μ₂
The alternative hypothesis is Hₐ: μ₁ > μ₂
Where;
= 13.5
= 12
σ₁ = 2.5
σ₂ = 1.5
We set our α level at 0.05
Therefore, our critical z = ± 1.96
For n₁ = n₂ = 23, we have;
We reject the null hypothesis at α = 0.05, as our z-value, 3.5969 is larger than the critical z, 1.96 or mathematically, since 3.5969 > 1.96
Therefore, there is enough statistical evidence to suggest that Alyse time is larger than Jocelyn in a 1 mile race on a randomly select day and the probability that Alyse has a larger time than Jocelyn is 0.99983
Therefore;
The probability that Alyse has a smaller time than Jocelyn is 1 - 0.99983 = 0.00017 = 1.7 × 10⁻⁴.