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weqwewe [10]
3 years ago
10

Algebraic expression the sum of 27 and twice the opposite of why

Mathematics
1 answer:
gogolik [260]3 years ago
4 0

27 + 2×(-why)

matches your English expression.

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7 points!!!! hep help help 2. When you are converting a decimal to a fraction, how do you know what to use as the denominator?
vitfil [10]

Step-by-step explanation:

Check to see if there is a number before (to the left of) the decimal. If there is, this number is the whole number of the fraction. So, 3 is the whole number. Place the number that falls after (to the right of) the decimal in the numerator; then use the decimal placement to determine the denominator.

3 0
3 years ago
Who’s good at algebra & can answer these with work??
AleksandrR [38]

Answer:

The answer to x2=25 is x=5

Step-by-step explanation:

When using factoring to solve this problem I just square rooted both numbers. The square root of x2 is x and the square root of 25 is 5. Sorry i couldn't help with all of them!

5 0
3 years ago
A bag has 4 red 3 white 2 blue and 1 green marble in it. Use this information to answer question 9-11.
love history [14]

#'s 9-14

Base info:   40% are red, 30% are white, 20% are blue, and 10% are green

9) 40% chance to get red, 10% chance to get green. 50% chance to get one of either.

10) getting red: 40%

Getting blue: 20%

11) 80%  (100% - 20% = 80%)

1/8 = 12.5%

12) 12.5% chance

13) 25% chance

14) 12.5 x 5 = 62.5  

62.5% chance

4 0
3 years ago
Read 2 more answers
If the second number is subtracted from the sum of the first number and 2 times the third number, the result is 1. The thrid num
weeeeeb [17]

Answer:

<h2>x = 0, y = 5, z = 3</h2>

Step-by-step explanation:

x,\ y,\ z-\text{three numbers}\\\\\left\{\begin{array}{ccc}(x+2z)-y=1&(1)\\z+2x=3&(2)\\x+3y+z=18&(3)\end{array}\right\\\\(2)\\z+2x=3\qquad\text{subtract}\ 2x\ \text{from both sides}\\z=3-2x\qquad(*)\\\\\text{Substitute}\ (*)\ \text{to (1) and (3)}\\\\\left\{\begin{array}{ccc}x+2(3-2x)-y=1&\text{use the distributive property}\\x+3y+(3-2x)=18\end{array}\right

\left\{\begin{array}{ccc}x+(2)(3)+(2)(-2x)-y=1\\x+3y+3-2x=18&\text{subtract 3 from both sides}\end{array}\right\\\left\{\begin{array}{ccc}x+6-4x-y=1&\text{subtract 6 from both sides}\\(x-2x)+3y=15\end{array}\right\\\left\{\begin{array}{ccc}(x-4x)-y=-5\\-x+3y=15\end{array}\right\\\left\{\begin{array}{ccc}-3x-y=-5&\text{multiply both sides by 3}\\-x+3y=15\end{array}\right

\underline{+\left\{\begin{array}{ccc}-9x-3y=-15\\-x+3y=15\end{array}\right}\qquad\text{add all sides of the equations}\\.\qquad-10x=0\qquad\text{divide both sides by (-10)}\\.\qquad\boxed{x=0}\\\\\text{Put it to the second equation:}\\-0+3y=15\\3y=15\qquad\text{divide both sides by 3}\\\boxed{y=5}\\\\\text{Put the value of}\ x\ \text{to}\ (*):\\\\z=3-2(0)\\\boxed{z=3}

7 0
3 years ago
PLEASE HELP ME! Find the cube roots of 125(cos 288° + i sin 288°).
shutvik [7]
◆ COMPLEX NUMBERS ◆

125 ( cos 288 + i sin 288 )  can be written as -

125.e^i( 288) 
125.e^i( 288 +360 ) 
125.e^i( 288+ 720)

[ As , multiples of 360 can be added to an angle without changing any trigonometric functions or sign ]

To find the cube root , take the cube root of above 3 expressions ,

We get -
5 e^( i 96 ) 
5 e^( i 216 )  
5 e^( i 336 )

Now using Euler's formula , We rewrite above as -

5 ( cos 96 + i sin 96 ) 
5(c os 216 + i sin 216 ) 
5 ( cos 336 + i sin 336 ) Ans.
6 0
3 years ago
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