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bulgar [2K]
3 years ago
7

PLEASE HELP ME WITH THIS MATH QUESTION

Mathematics
1 answer:
AURORKA [14]3 years ago
7 0
The general formula of an Arithmetic sequence is:

a_{n}= a_{1}+(n-1)*d

Comparing this formula with the given formula, we can write:

Common Difference = d = 5

Since, every term of an Arithmetic sequence can be obtained by adding the common difference to the previous term, so we can write the recursive formula as: 

a_{n} = a_{n-1} +d

For the given sequence we can write:

x_{n} = x_{n-1} +5

So, the answer to this question is 5
You might be interested in
Find the missing angle.
notsponge [240]

Answer:

y=51, z and x= 129

Step-by-step explanation:

its complicated, but try to think of it as 51 and x/z are complementary angles, meaining they are on the same line, which means they equal 180, which makes this easier to solve meaning all you have to do is subtract 180-51=129.

6 0
3 years ago
Read 2 more answers
Question 2(Multiple Choice Worth 5 points)
Mamont248 [21]

Answer:

If you mean:

x² = 10

√x² = √10

x = √10

if you meant:

2x = 10

2x/2 = 10/2

x = 10/2

x = 5

hope this helps

If you mean x^2 then there would be no answer after all, 3^2= 9 and 4^2= 16 so

If you mean 2x then the answer would be 5

Step-by-step explanation:

:0

3 0
2 years ago
The position function of a particle in rectilinear motion is given by s(t) = 2t^3 + 21t^2 + 60t + 3 for t ≥ 0 with t measured in
natta225 [31]
As the fellow above said, the particle does make a U-turn at the vertex, and we can find that out by getting the derivative of s(t) and zeroing it out to get the point of the horizontal tangent.

Bearing in mind that ds/dt is really v(t) or the velocity equation, so when we zero out the ds/dt, is the same as saying the velocity went to 0, since it got zeroed out, and then the particle goes over the vertex and changes direction.

\bf s(t)=2t^3-21t^2+60t+3\implies \boxed{\cfrac{ds}{dt}=6t^2-42t+60}\leftarrow v(t)
\\\\\\
0=6t^2-42t+60\implies 0=t^2-7t+10\implies 0=(t-5)(t-2)
\\\\\\
t=
\begin{cases}
5\\
2
\end{cases}\impliedby \textit{it makes the first turn at the \underline{2 second}}
\\\\\\
\textit{now let's find the acceleration equation, a(t)}
\\\\\\
\boxed{\cfrac{d^2s}{dt^2}=12t-42}\leftarrow a(t)\\\\
-------------------------------\\\\
s(2)=55\qquad \qquad \qquad \qquad a(2)=-18

the negative acceleration value, simply means a decreasing rate of change, so, it means the particle is slowing down and possibly coming to a stop before changing direction again.
8 0
3 years ago
Twice x, plus 8, is the sum as -10
Fofino [41]

Answer:

×=-9

Step-by-step explanation:

2x+8=-10

2x=-18

×=-9

3 0
4 years ago
Read 2 more answers
2(m + 3n) + 2(m -6n)
Travka [436]
The answer (simplified) would be ~4m-6n~

Hope this helps

Have a great day/night
3 0
3 years ago
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