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miskamm [114]
3 years ago
5

For a line that goes through points (2,-2) and (1.-6), what is the equation

Mathematics
1 answer:
sesenic [268]3 years ago
4 0

Answer:

y + 6 = 4[x - 1]\:or\:y + 2 = 4[x - 2]

Step-by-step explanation:

First find the <em>rate of</em><em> </em><em>change</em><em> </em>[<em>slope</em>]:

\frac{-y_1 + y_2}{-x_1 + x_2} = m

\frac{2 - 6}{-2 + 1} = \frac{-4}{-1} = 4

Then plug each of these coordinates into the Point-Slope Formula, y - y_1 = m[x - x_1]. Now remember, in this formula, all the negative symbols give the OPPOSITE terms of what they really are, so be EXTREMELY CAREFUL inserting the coordinates into the formula with their CORRECT SIGNS:

y + 6 = 4[x - 1]\:or\:y + 2 = 4[x - 2]

I am joyous to assist you anytime.

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Select the correct answer from each drop-down menu.
serious [3.7K]

Answer:

Center: (4,8)

Radius: 2.5

Equation: (x-4)^2+(y-8)^2=6.25

Step-by-step explanation:

It was given that; the endpoints of the longest chord on a circle are (4, 5.5) and (4, 10.5).

Note that the longest chord is the diameter;

The midpoint of the ends of the diameter gives us the center;

Use the midpoint formula;

(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )

The center is at; (\frac{4+4)}{2} ,\frac{5.5+10.5}{2}=(4,8)

To find the radius, use the distance formula to find the distance from the center to one of the endpoints.

The distance formula is;

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

r=\sqrt{(4-4)^2+(10.5-8)^2}

r=\sqrt{0^2+(2.5)^2}

r=\sqrt{0^2+(2.5)^2}=2.5

The equation of the circle in standard form is given by;

(x-h)^2+(y-k)^2=r^2

We substitute the center and the radius into the formula to get;

(x-4)^2+(y-8)^2=2.5^2

(x-4)^2+(y-8)^2=6.25

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3 years ago
Which of the following equations was used to graph the line shown?
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Lines l and m are parallel lines cut by the transversal line t. Which angle is congruent to ∠7?
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Step-by-step explanation:

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A recipe requires 3 cups of flour to make 27 dinner rolls. How much flour is needed to make 9 rolls?
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Find two numbers whose sum is 25 and the sum of whose reciprocals is 1/6
Katen [24]

Answer:

10 and 15

Step-by-step explanation:

Let 'x' and 'y' are the numbers we need to find.

x + y = 25 (two numbers whose sum is 25)

(1/x) + (1/y) = 1/6 (the sum of whose reciprocals is 1/6)

The solutions of the this system of equations are the numbers we need to find.

x = 25 - y

1/(25 - y) + 1/y = 1/6 multiply both sides by 6(25-y)y

6y + 6(25-y) = (25-y)y

6y + 150 - 6y = 25y - (y^2)

y^2 - 25y + 150 = 0 quadratic equation has 2 solutions

y1 = 15

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Thus we have :

First solution: for y = 15, x = 25 - 15 = 10

Second solution: for y = 10, x = 25 - 10 = 15

The first and the second solution are in fact the same one solution we are looking for: the two numbers are 10 and 15 (since the combination 10 and 15 is the same as 15 and 10).

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