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3 years ago

Please Answer this asap

Mathematics

2 answers:

Gnom [1K]3 years ago

7 0

It should be skewed left

faust18 [17]3 years ago

4 0

It’s skewed to the left

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Find the value of x PLEASE EXPLAIN

Wewaii [24]

Answer:

x = 57, x = 111

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180°

Sum the 3 angles and equate to 180, that is

x + 67 + 56 = 180

x + 123 = 180 ( subtract 123 from both sides )

x = 57

---------------------------------------------------------------------

Similarly

x + 47 + 22 = 180

x + 69 = 180 ( subtract 69 from both sides )

x = 111

6 0

3 years ago

Read 2 more answers

At a construction job for a mall there are 45 painters. Of these painters, 18 of them are painting the interior of the mall. Wha

Jlenok [28]

Answer:

40%

Step-by-step explanation:

18/45 × 100

2/5 × 100

40%

8 0

3 years ago

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ဇကis2/4 greater than or less than 2/3<br>

kicyunya [14]

Answer: 2/4 is less than 2/3

8 0

3 years ago

A simple random sample of size nequals81 is obtained from a population with mu equals 83 and sigma equals 27. (a) Describe the

Ivanshal [37]

Answer:

a) $\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

b) $z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

c) $z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

d) $z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

Step-by-step explanation:

For this case we know the following propoertis for the random variable X

$\mu = 83, \sigma = 27$

We select a sample size of n = 81

Part a

Since the sample size is large enough we can use the central limit distribution and the distribution for the sampel mean on this case would be:

$\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

Part b

We want this probability:

$P(\bar X>89)$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 89 we got:

$z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

Part c

$P(\bar X$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 75.65 we got:

$z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

Part d

We want this probability:

$P(79.4 < \bar X < 89.3)$

We find the z scores:

$z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

8 0

3 years ago

I need a little extra help with number three

diamong [38]

Answer:

The answer to your question is:

Step-by-step explanation:

Data

f(x) = -2x² + 8x - 2

Process

-2x² + 8x = y + 2

-2(x² - 4x + 4) = y + 2 - 8

-2(x - 2)² = y - 6

(x - 2)² = 1/2 (y - 6)

Vertex = (2, 6)

Axis of symmetry = x = 2

y-intercept

f(0) = -2(0)² + 8(0) - 2

f(0) = 0 + 0 - 2

f(0) = -2

Domain (-∞, ∞)

Range (-∞, 6]

See the graph below

6 0

3 years ago