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Vaselesa [24]
3 years ago
15

Define a minor arc. How do you name a minor arc?

Mathematics
2 answers:
Sonja [21]3 years ago
7 0
A minor arc is defined as an arc of a circle that consists of a measurement less than or equal to radians. The measure of a minor arc is always less than 180 degrees. When naming a minor arc, you should two letters on the circle. Major arcs and semicircles use three letters. 
aleksklad [387]3 years ago
5 0

Answer:

If the arc length is less than 180 degrees, then it is called minor arc.

Minor arc length = m(AB), where "A" and "B" are the end points of the arc length.

Step-by-step explanation:

If you take two points on the circle and connect the points to the center of the the circle (radius). You will get the arc length subtend by the radi.

If the arc length is less than 180 degrees, then it is called minor arc.

If the arc length is greater than 180 degrees, then it is called major arc.

Minor arc is shortest arc length and major arc is the longest arc length.

The arc length marked with the endpoints of the arc length.

If you name the two points A and B of the minor arc.

The measure of the minor arc length represented by  m(AB)

Herewith I have attached the figure.

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6 0
1 year ago
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3 years ago
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Blizzard [7]

Answer:

Probability is:   $ \frac{\textbf{13}}{\textbf{51}} $

Step-by-step explanation:

From a deck of 52 cards there are 26 black cards. (Spades and Clubs).

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First, we determine the probability of drawing a black card.

P(drawing a black card) = $ \frac{number \hspace{1mm} of  \hspace{1mm} black  \hspace{1mm} cards}{total  \hspace{1mm} number  \hspace{1mm} of  \hspace{1mm} cards} $  $ = \frac{26}{52} = \frac{\textbf{1}}{\textbf{2}} $

Now, since we don't replace the drawn card, there are only 51 cards.

But the number of red cards is still 26,

∴ P(drawing a red card) = $ \frac{number  \hspace{1mm} of  \hspace{1mm} red  \hspace{1mm} cards}{total  \hspace{1mm} number  \hspace{1mm}of  \hspace{1mm} cards} $  $ = \frac{26}{51}  $

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$ = \frac{\textbf{13}}{\textbf{51}} $

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WARRIOR [948]

Answer:

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2 years ago
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