30. how much does it cost to light a 300-w light bulb for 30 days if the cost of electricity is 7 cents per kwh
1 answer:
You might be interested in
3(r-6) +2 = 4(r+2) -21
3r - 6r +2 = 4r +8 -21
-3r +2 = 4r -13
2 = 7r -13
15 = 7r
r =
r = 7.5
3r - 6r +2 = 4r +8 -21
-3r +2 = 4r -13
2 = 7r -13
15 = 7r
r =
r = 7.5
