Can someone help please.
2 answers:
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Answer:
The smallest sample size n that will guarantee at least a 90% chance of the sample mean income being within $500 of the population mean income is 48.
Step-by-step explanation:
The complete question is:
The mean salary of people living in a certain city is $37,500 with a standard deviation of $2,103. A sample of n people will be selected at random from those living in the city. Find the smallest sample size n that will guarantee at least a 90% chance of the sample mean income being within $500 of the population mean income. Round your answer up to the next largest whole number.
Solution:
The (1 - <em>α</em>)% confidence interval for population mean is:
The margin of error for this interval is:
The critical value of <em>z</em> for 90% confidence level is:
<em>z</em> = 1.645
Compute the required sample size as follows:
Thus, the smallest sample size n that will guarantee at least a 90% chance of the sample mean income being within $500 of the population mean income is 48.
Answer:
Step-by-step explanation:
In this problem we have a exponential function of the form
where
x is the time in hours
y is the numbers of bacteria
a is the initial value
b is the base
r is the rate of growth
b=(1+r)
we have that
For x=8, y=3,300
substitute in the exponential function
solve for b
Find the value of r
The equation is equal to
For x=12 hours
substitute the value of x in the equation