Answer:
t = 4
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define equation</u>
t + t + t = 12
<u>Step 2: Solve for </u><em><u>t</u></em>
- Combine like terms (t): 3t = 12
- Divide 3 on both sides: t = 4
<u>Step 3: Check</u>
<em>Plug in t into the original equation to verify it's a solution.</em>
- Substitute in <em>t</em>: 4 + 4 + 4 = 12
- Add: 8 + 4 = 12
- Add: 12 = 12
Here we see that 12 does indeed equal 12.
∴ t = 4 is a solution of the equation.
I am pretty sure the answer would be -.02
Bc you would do 2-3.6/5- -3
Answer:
P = 0.4812
Step-by-step explanation:
First, we need to use here two expressions and then do the calculations.
The first one is the conditional probability which is:
P(B|A) = P(A∩B)/P(A) (1)
The second expression to use has relation with the Bayes's theorem which is the following:
P(D|C) = P(C|D)*P(D) / P(C|D)*P(D) + P(C|d)*P(d) (2)
Now, the expression (2) is the one that we will use to calculate the probability of a selected random bicyclist who tests positive for steroids.
So, in this case, we will call C for positive and D that is using steroids and d is the opposite of d, which means do not use steroids.
Then, the probabilities are the following:
P(D) = 8% or 0.08
P(C|D) = 96% or 0.96
P(C|d) = 9% or 0.09
P(d) = 1 - 0.08 = 0.92
With these data, let's replace in expression 2
P(D|C) = 0.96 * 0.08 /0.96 * 0.08 + 0.09*0.92
P(D|C) = 0.0768 / 0.1596
P(D|C) = 0.4812 or 48.12%
6 because 1 in 1/6 represents how many he took and the denominator in the other fractions gets smaller because it's less and less each time
Answer:
Since the calculated z =-3.5357 falls in the critical region z ≥ 1.645 we reject H0 and conclude that the sample provides sufficient evidence to indicate that the true percentage of all firms that announced one or more acquisitions during the year 2000 is ≥ 30%
Step-by-step explanation:
<u><em>Testing hypothesis about a population proportion when sample size is large.</em></u>
If the sample size is large then the variable
z= p^-p / sqrt [pq/n]
is approximately standard normal.
Formulate the hypotheses as
H0 : p < 30% against the claim Ha: p ≥ 30%
Choose the significance level ∝= 0.05
the critical region is z ≥ 1.645 because the alternative hypothesis is stated on a greater than or equal to basis.
Computing
Z= 748-(2778*0.3)/ √2778*30/100*70/100
z= 748-833.4/√583.38
z= -85.4/24.153
z=-3.5357
Since the calculated z =-3.5357 falls in the critical region z ≥ 1.645 we reject H0 and conclude that the sample provides sufficient evidence to indicate that the true percentage of all firms that announced one or more acquisitions during the year 2000 is ≥ 30%
The p- value is 0.0002
