Answer:
Mixture problemsare ones where two different solutions are mixed together ... should be added to the first in order to get amixture of 5% salt?4) How much ... 8 6) How many grams of pure acid must be added to 40 grams of a 20% acidsolution to ... make a Mixture that perliter?15) Solution A is 50% acid and solution B is 80% ...
Step-by-step explanation:
Answer: 14.5
Step-by-step explanation:
If we divide 58x by 4, our answer would be 14 and a half. Which is same thing as 14.5.
= 58x/4
x = 14.5