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3 years ago

PLEASE ANSWER + BRAINLIEST!!

Mathematics

1 answer:

marshall27 [118]3 years ago

7 0

X^4 + 2x^2 - 24
= (x^2 + 6)(x^2 - 4)
= (x^2 + 6)(x - 2)(x + 2)

x^4 - 9x^2 + 18
= (x^2 - 6)(x^2 - 3)

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Consider three boxes with numbered balls in them. Box A con- tains six balls numbered 1, . . . , 6. Box B contains twelve balls

murzikaleks [220]

Answer:

a) 0.73684

b) 2/3

Step-by-step explanation:

part a)

$P ( A is 1 / exactly two balls are 1) = \frac{P ( A is 1 and that exactly two balls are 1)}{P (Exactly two balls are one)}$

Using conditional probability as above:

(A,B,C)

Cases for numerator when:

P( A is 1 and exactly two balls are 1) = P( 1, not 1, 1) + P(1, 1, not 1)

= $(\frac{1}{6}* \frac{11}{12}*\frac{1}{4}) + (\frac{1}{6}*\frac{1}{12}*\frac{3}{4}) = 0.048611111$

Cases for denominator when:

P( Exactly two balls are 1) = P( 1, not 1, 1) + P(1, 1, not 1) + P(not 1, 1 , 1)

$= (\frac{1}{6}* \frac{11}{12}*\frac{1}{4}) + (\frac{1}{6}*\frac{1}{12}*\frac{3}{4}) + (\frac{5}{6}*\frac{1}{12}*\frac{1}{4})= 0.0659722222$

Hence,

$P ( A is 1 / exactly two balls are 1) = \frac{P ( A is 1 and that exactly two balls are 1)}{P (Exactly two balls are one)} = \frac{0.048611111}{0.06597222} \\\\= 0.73684$

Part b

$P ( B = 12 / A+B+C = 21) = \frac{P ( B = 12 and A+B+C = 21)}{P (A+B+C = 21)}$

Cases for denominator when:

P ( A + B + C = 21) = P(5,12,4) + P(6,11,4) + P(6,12,3)

$= 3*P(5,12,4 ) =3* \frac{1}{6}*\frac{1}{12}*\frac{1}{4}\\\\= \frac{1}{96}$

Cases for numerator when:

P (B = 12 & A + B + C = 21) = P(5,12,4) + P(6,12,3)

$= 2*P(5,12,4 ) =2* \frac{1}{6}*\frac{1}{12}*\frac{1}{4}\\\\= \frac{1}{144}$

Hence,

$P ( B = 12 / A+B+C = 21) = \frac{\frac{1}{144} }{\frac{1}{96} }\\\\= \frac{2}{3}$

4 0

3 years ago

PLASE NEED HELP FAST

icang [17]

Answer:

Step-by-step explanation:

w / h = u / HG

w = 8

h = 48

u = 5

lets use h / w = HG / u this is the same relationship but looks easier to me

48/8 = HG / 5

6 = HG / 5

6 * 5 = HG

30 = HG

not too tuff... when you set the relationship so it's easiest :)

and yes.. we cold have swapped the fractions and done it the other way and gotten the same answer.. but maybe with a bit more algebra.. and... avoid extra algebra ... that's where the mistakes can be made :P

8 0

3 years ago

A meuseum had x visitors on friday. On Saturday it had 150 more visitors than it did on friday. The total number of visitors on

ANTONII [103]

Answer:

75 people.

Step-by-step explanation:

If Friday is x, then Saturday is 150 + x. The number of people on Sunday then is (Friday + Saturday)/2, thus (x + (150 + x))/2. This then simplifies to (x + 150 + x)/2 ---> (2x + 150)/2 ---> 2x/2 + 150/2 ---> x + 75. So, Friday is x and Sunday is x + 75, to find out how many more visitors the museum have on Sunday than Friday, you subtract the two numbers. (x + 75) - x = 75.

8 0

4 years ago

Un cono ha l'area laterale di 255 pigreco cm^2, l'apotema di 17 cm e pesa 900 pigreco g. Calcola il peso specifico del materiale

valkas [14]

Answer:

The specific weight is $1.5\frac{g}{cm^{3}}$

Step-by-step explanation:

The question in English

A cone has a lateral area of 255 pi cm^2, an apothem of 17 cm and weighs 900 pi g. It calculates the specific weight of the material of which it is composed

step 1

Find the radius of the cone

we know that

The lateral area of a cone is equal to

$LA=\pi rl$