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bonufazy [111]
3 years ago
11

I need help with algebra

Mathematics
1 answer:
Serga [27]3 years ago
6 0
First, you need to isolate the variable. 

Subtract four from both sides of the equation.    x/2 = -3
Multiply both sides by two.    x = -6

Substitute to check your answer.
4 + (-6)/2 = 1
4 + -3 = 1
1 = 1

Our solution is correct

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The variance is given by:

Var(X) = \frac{(b-a)^2}{12}= \frac{(12-10)^2}{12}= 0.3333

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b) P(X

And we can use the cumulative distribution function given by:

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And using this function we got:

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And using the complement rule and the cumulative distribution function we got:

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Step-by-step explanation:

For this case we define the random variable X=quantity put in each bag , and we know that the distribution for X is given by:

X \sim Unif (a= 10, b =12)

Part a

The expected value is given by:

E(X) =\frac{a+b}{2}= \frac{10+12}{2}= 11

The variance is given by:

Var(X) = \frac{(b-a)^2}{12}= \frac{(12-10)^2}{12}= 0.3333

And the standard deviation is just the square root of the variance and we got:

Sd(x) = \sqrt{0.3333}= 0.5774

Part b

For this case we want this probability:

P(X

And we can use the cumulative distribution function given by:

F(x) = \frac{x-a}{b-a}, a \leq x \leq b

And using this function we got:

P(X

Part c

For this case we want this probability:

P(X>10.5)

And using the complement rule and the cumulative distribution function we got:

P(X>10.5)= 1-P(X

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Answer:

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