Answer:
The output is "A"
Explanation:
public class Solution {
public static void main(String args[]) {
mystery(7);
}
public static void mystery(int a) { System.out.println("A"); }
public static void mystery(double a) { System.out.println("B"); }
public static void mystery(int a, double b) { System.out.println("C"); }
public static void mystery(double a, int b) { System.out.println("D"); }
}
In the code above; mystery is defined in four different ways called method overloading. Method overloading is when same method is defined with different parameters.
In the first case; mystery will be called if the argument is int.
In the second case; mystery will be called if the argument is double.
In the third case; mystery will be called if the arguments are int and double.
In the fourth case; mystery will be called if the arguments are double and int.
When mystery(7) is called; the mystery method requiring only int will be called and the output is "A".
Answer:
The term "savanna" is often used to refer to open grassland with some tree cover, while "grassland" refers to a grassy ecosystem with little or no tree cover.
Explanation:
Answer:
Tab: Home Tab
Command Group: Paragraph
Icon: Justify Icon
<em>The icon has no name; rather it is represented by 4 horizontal lines that are aligned on both edges</em>
<em />
Explanation:
To answer this question, I'll make use of the following attachment
<em>Where</em>
<em>1- represents the home tab</em>
<em>2 - represents the paragraph</em>
<em>3 - represents the justify icon</em>
<em />
Answer:
error: incompatible types
Explanation:
Given
The attached code
Required
The output
Variable "a" is declared as float
While p is declared as a pointer to an integer variable
An error of incompatible types will be returned on line 3, <em>int *p = a;</em>
Because the variables are not the same.
To assign a to p*, we have to use type casting.
Hence, (b) is correct
