What is the x intercept of the line y=5x+6

A cubic function "y" has real coefficient, and its zeros are 0, 1, and -4. If x = 5 and y = 540 satisfies its equation, find the

sertanlavr [38]

Let's begin by listing out the information given to us:

A cubic function has the general form of:

$\begin{gathered} \displaystyle f(x)=ax^3+bx^2+cx+d \\ f(x)=y \\ y=ax^3+bx^2+cx+d \end{gathered}$

The function has real coefficients

Its zeros are 0, 1 & -4

$undefined$

4 0

1 year ago

Please help I’m so close to passing math

photoshop1234 [79]

Answer:I think it’s 2 the best buy

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Which statements are true the order pair (1,2) and the system of equations? y=2x+4 7x-2y=3

Stolb23 [73]

Answer:

The Correct Answers are

When (1 ,2) is substituted into the first equation, the equation is true.

When (1 ,2) is substituted into the second equation, the equation is true.

Step-by-step explanation:

Given:

$y=2x+4$ ..............Equation ( 1 )

$7x-2y=3$ .............Equation ( 2 )

To Show:

order pair ( 1, 2) True for Which Equation

Solution:

The Correct Statements are

When (1 ,2) is substituted into the first equation, the equation is true.

For Equation ( 1 )

Put x = 1 and y =2 in equation 1 we get

$2 = -2\times 1+4$

$2 =2$

∴ Left hand side = Right hand side

Hence True

When (1 ,2) is substituted into the second equation, the equation is true.

For Equation ( 2 )

Put x = 1 and y = 2 in equation 2 we get

$7\times 1-2\times 2 =3$

$3=3$

∴ Left hand side = Right hand side

Hence True

The ordered pair (1 , 2) is a solution to the system of linear equations.

∴ From above Both are True,

Hence True

5 0

3 years ago

What is 500,000-437,981 step by step

ElenaW [278]

500,000-437,981=62,019

3 0

3 years ago

Read 2 more answers

Security A rounds every 2 minutes and 20 seconds in the gate 1. Security B rounds every 1 minute and 40 seconds in the gate 2. I

Elden [556K]

Answer:

$Time = 11\frac{2}{3}\ min$

Step-by-step explanation:

Given

$Security\ A = 2\ mins, 20\ secs$

$Security\ B = 1\ mins, 40\ secs$

Required

After how many minutes, will they round together

First, convert the given time to minutes

$Security\ A = 2\ mins, 20\ secs$

$Security\ A = 2\ mins+ 20\ secs$

$Security\ A = 2\ mins+ \frac{20}{60}\ min$

$Security\ A = 2\ mins+ \frac{1}{3}\ min$

$Security\ A = 2\frac{1}{3}\ min$

$Security\ B = 1\ mins, 40\ secs$

$Security\ B = 1\ mins+ 40\ secs$

$Security\ B = 1\ mins+ \frac{40}{60}\ min$

$Security\ B = 1\frac{2}{3}\ min$

So, we have:

$Security\ A = 2\frac{1}{3}\ min$

$Security\ B = 1\frac{2}{3}\ min$

List out the multiples of the time of both security personnel take round.

$Security\ A = 2\frac{1}{3}min,\ 4\frac{2}{3}min,\ 7min,\ 9\frac{1}{3}min,\ 11\frac{2}{3}min...$

$Security\ B = 1\frac{2}{3}min,\ 3\frac{1}{3}min,\ 5min,\ 6\frac{2}{3}min,\ 8\frac{1}{3}min,\ 10min\ ,11\frac{2}{3}min,...$

In the above lists, the common time is:

$Time = 11\frac{2}{3}\ min$

This implies that they go on round after $11\frac{2}{3}\ min$

4 0

3 years ago