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2 years ago

Express log2 64-log2 4 as a simple logarithm

1 answer:

4 0

Express log(2)64-log(2)4 as a single logarithm.
Simplify as possible.
Solution:

= log(2)[64/4]
= log(2)[16]
= 4

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Find the distance between (-5,6)and (3,2).

skad [1K]

Answer:

$\displaystyle d = 4\sqrt{5}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Coordinates (x, y)

Algebra II

Distance Formula: $\displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Step-by-step explanation:

Step 1: Define

Point (-5, 6) → x₁ = -5, y₁ = 6

Point (3, 2) → x₂ = 3, y₂ = 2

Step 2: Find distance d

Simply plug in the 2 coordinates into the distance formula to find distance d

Substitute in points [Distance Formulas]: $\displaystyle d = \sqrt{(3+5)^2+(2-6)^2}$
[Distance] [√Radical] (Parenthesis) Add/Subtract: $\displaystyle d = \sqrt{(8)^2+(-4)^2}$
[Distance] [√Radical] Evaluate exponents: $\displaystyle d = \sqrt{64+16}$
[Distance] [√Radical] Add: $\displaystyle d = \sqrt{80}$
[Distance] [√Radical] Simplify: $\displaystyle d = 4\sqrt{5}$

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3 years ago

If w is a string of english letters a–z (all uppercase for the purposes of this problem), let wr denote the reverse of w; (train

Dennis_Churaev [7]

Answer:

$f(x)=\left \{\begin{array}{rl}26^{\frac{k}{2}}&\text{for k even}\\26^{\frac{k+1}{2}}&\text{for k odd}\end{array}\right.$

Step-by-step explanation:

Half the length of the palindrome can be any possible sequence of the 26 available letters. The other half is constrained to be the reverse of the same sequence. For odd length sequences, the middle letter can be any of the 26.

So, for k even, the number of palindromes is 26^(k/2). For k odd, the number is 26·26^((k-1)/2) = 26^)((k+1)/2).

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