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madreJ [45]
3 years ago
7

Express log2 64-log2 4 as a simple logarithm

Mathematics
1 answer:
Triss [41]3 years ago
4 0
<span>Express log(2)64-log(2)4 as a single logarithm.
Simplify as possible.
Solution: 

 = log(2)[64/4] 
= log(2)[16]
= 4
</span>
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Which of the following is not preserved under a dilation?
Helga [31]
C distance is the only thing that isn't preserved under a dilation

3 0
2 years ago
12(3-2x)=84 solve for x.
OlgaM077 [116]
12(3-2x) = 84

do distributive multiplication:

12(3) + 12(-2x) = 84
36 - 24x = 84

Deduct 36 to both sides

36 - 36 - 24x = 84 - 36
-24x = 48

divide -24 to both sides

-24x / -24 = 48/-24
x = -2

To check:
12(3-2x) = 84
12(3-2(-2) = 84
12(3+4) = 84
12(7) = 84
84 = 84
7 0
3 years ago
Read 2 more answers
At 7:00 A.M., Alicia pours a cup of tea whose temperature is 200°F. The tea starts to cool to room temperature (72°F). At 7:02 A
NeTakaya

Answer:

Part A

The most correct option is;

b. y = 128(0.989)x + 72

Part B

Ella can drink the tea after 7:22

Step-by-step explanation:

Here we have the temperature variation with time given in an exponential equation as follows;

Let the temperature at time x (in minutes) = y

Therefore, y = a × mˣ + b

Where:

b = Shift of the curve or the limit value of the decreasing exponential function as x → ∞

When y = 200, x = 0

Therefore. 200 = a × m⁰ + c = a + c

We note that c is the shift of the graph, the value upon which temperature increases = final temperature = 72°F

Hence a = 200 - 72 = 128°F

When y = 197, x = 2 minutes

Therefore, 197 = 128·m² + 72 =

m² = (197 - 72)/128 = 125/128

m = √(125/128) = 0.98821

Hence the exponential equation of cooling is presented in the following equation;

y = 128 × (0.98821)ˣ + 72

Therefore, the most correct option is b. y = 128(0.989)x + 72

Part B

When the temperature is 172°F we have;

172 = 128 × (0.989)ˣ + 72

∴ (0.989)ˣ = (172 - 72)/128 = 100/128 = 25/32

log(0.989)ˣ = log(25/32)

x·log(0.989) = log(25/32)

x = log(25/32)/log(0.989) = 22.32 minutes

Hence Ella can drink the tea after 7:22.

6 0
3 years ago
I dO nOt coMprEheNd PLEASE HELPPP
jasenka [17]
Lines y=-x+2 and y=3x+1 intersect the y=axis. If you plot them out on a graph using the equation y=mx+b, then they are parallel and are set on the y-axis.
3 0
3 years ago
Rewrite each equation in slope-intercept form, if necessary. Then determine whether the lines are parallel. Explain,
Oksana_A [137]
Answer:
d

Step-by-step explanation:

Slope intercept form: y = mx + b

y = -x + 7
x + y = 21

x + y = 21
-x -x
y = -x + 21


y = -x + 7
y = -x + 21

Parallel lines have the same slope. Here, our slope is -1

Therefore, our final answer is d.


Hope this helps!
8 0
2 years ago
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