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topjm [15]
4 years ago
12

PLEASE HELP 50 POINTS!!

Mathematics
2 answers:
Galina-37 [17]4 years ago
8 0

Answer: 225

<u>Step-by-step explanation:</u>

n₁ = 2(1) - 1

    = 2 - 1

    = 1

n₁₅ = 2(15) - 1

     = 30 - 1

      = 29

S_{15} =\frac{n_{1}+ n_{15}}{2}*15

   =\frac{1+29}{2}*15

    =\frac{30}{2}*15  

    = 15 * 15

     = 225  

zalisa [80]4 years ago
6 0
<h3>- - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - </h3>

➷ The sum would be 225

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

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Helen [10]
The answer would be 60, if you add 13,15, and 12 up you get 40. Those numbers would be considered 2/3 of all the marbles. Divide 40 by 2 to get how many marbles is 1/3. You would get 20 being a third if the marbles. Add that to the original 40 and you’ll get a total of 60.
5 0
3 years ago
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When I double my number and then subtract the result from five , I get negative one. What is my number? Write and solve an equat
Vikentia [17]

Answer:

3

Step-by-step explanation:

5-2x=-1

(x is your number)

5-5=0

-1-5=-6

-2x=-6

-2x/-2=x

-6/-2=3

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3 0
3 years ago
Delta makes 12-volt car batteries. These batteries are known to be normally
blondinia [14]

Answer:

The probability that Delta car batteries last between three and four years

P(36≤X≤48) = 0.5188

The percentage of that Delta car batteries last between three and four years

P(3≤X≤4) = 52%

Step-by-step explanation:

<u><em>Step(i):-</em></u>

<em>Given that the sample size n =12 -volt car batteries</em>

<em>Let  'X' be a Random variable in a normal distribution</em>

<em>Given that mean of the normal distribution = 45 months</em>

<em>Given that the Standard deviation of the normal distribution = 8months</em>

<u><em>Step(ii):-</em></u>

Let  X₁ = 3 years = 12 × 3 = 36 months

Z_{1} = \frac{x_{1} -mean}{S.D} = \frac{36-45}{8} = -1.125

Let X₂ = 4 years  = 12 × 4 = 48 months

Z_{2} = \frac{x_{2} -mean}{S.D} = \frac{48-45}{8} = 0.375

<u><em>Step(iii)</em></u>:-

The probability that Delta car batteries last between three and four years

P(36≤X≤48) = P(-1.125≤Z≤0.375)

                   = P(Z≤0.375) - P(Z≤-1.125)

                   = 0.5 +A(0.375) - (0.5-A(1.125)

                   = 0.5 + 0.1480 - (0.5 -0.3708)

                  = 0.1480 + 0.3708

                 = 0.5188

<u><em>Final answer:-</em></u>

The probability that Delta car batteries last between three and four years

P(36≤X≤48) = 0.5188

The percentage of that Delta car batteries last between three and four years

P(3≤X≤4) = 52%

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5 0
3 years ago
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OverLord2011 [107]
1/10 of a fluid ounce or 0.10
8 0
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From 309 grams to 299 grams.
Tom [10]

Answer: 3 percent decrease. = 0% Increase or a 5 % decrease.

Step-by-step explanation: Sorry, I don't have an explanation!

3 0
4 years ago
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