Since the 3 lengths of the triangle are given, one can use the Cosine law:
b^2 = a^2 + c^2 -2ac cos(B)
18^2 = 22.5^2 + 13.6^2 -2(22.5)(13.6) cos(B)
B = 53.12 deg
Using Sine law for C
18/(sin (53.12)) = 13.6/(sin ( C))
C = 37.19 deg
9514 1404 393
Answer:
C. 41.0, θ = 77.3°
Step-by-step explanation:
The sum is ...
5(8, 4) -3(-3, -4) +8(-5, 1) = (5·8-3(-3)+8(-5), 5·4-3(-4)+8·1)
= (40+9-40, 20+12+8) = (9, 40)
The magnitude is ...
√(9² +40²) = √1681 = 41
The angle is ...
arctan(40/9) ≈ 77.3°
The resultant magnitude and direction is 41∠77.3°.
The answer would be $27.07.
first you have to multiply 31.84 x .15 You should get 4.77
then subtract. 31.84-4.77=27.07
No values of X would answer this problem.
10x+1=10x+2
-10x -10x
3 = 0
