2 years ago

Brad bought a toy truck and toy car for $8.72 the car cost $4.85 how much did the toy truck cost?

Mathematics

1 answer:

Gekata [30.6K]2 years ago

7 0

Answer:

the answer is B. 3.87

Step-by-step explanation:

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1. 8y = 48<br> 2. q — 12 = 1<br> 3. 18 = a/2<br> 4. r/3 = 7<br> 5. 11 = m — 4

Nookie1986 [14]

Hello!

1. 8y = 48 => y = 48 : 8 => y = 6

2. q - 12 = 1 => q = 1 + 12 => q = 13

3. 18 = a/2 => a = 18 × 2 => a = 36

4. r/3 = 7 => r = 3 × 7 => r = 21

5. 11 = m - 4 => m = 11 + 4 => m = 15

Good luck! :)

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2 years ago

At noon, ship A is 130 km west of ship B. Ship A is sailing east at 25 km/h and ship B is sailing north at 20 km/h. How fast is

Hitman42 [59]

Answer:

answer = 12.87 km/h

Step-by-step explanation:

Given

Ship A is sailing east at 25 km/h = $\frac{dx}{dt}$

ship B is sailing north at 20 km/h = $\frac{dy}{dt}$

here x and y are the sailing at t = 4 : 00 pm for ship A and B respectively

so we get x = 4 ×25 =100 km/h

y = 4× 20 = 80 km/h

let z is the distance between the ships, we need to find $\frac{dz}{dt}$ at t = 4 hr

At noon, ship A is 130 km west of ship B (12:00 pm)

so equation will be

$z^2 = (130-x)^2 + y^2......................(i)\\put x = 100 and y = 80 \\\\we | | get \\$

$z^2 = 30^2 + 80^2\\z =\sqrt{7300} km/h$

derivative first equation w . r. to t we get

$2z\frac{dz}{dt} =$ $-2(130-x)\frac{dx}{dt}$ $+2y\frac{dy}{dt}$

$\frac{dz}{dt} =\frac{1}{z}[(x -130)\frac{dx}{dt} +y\frac{dy}{dt}]$

$\frac{dz}{dt} = \frac{( -20\times25 + 80\times20)}{\sqrt{7300} }$

$= \frac{1100}{85.44}\\ = 12.87km/h$

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