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3 years ago

If y=6x and x=1.5 find y

Mathematics

2 answers:

Vladimir [108]3 years ago

6 0

This awnser = 9 for ur equation

Karolina [17]3 years ago

4 0

Y=6x
x=1.5
y= 6x1.5 =9

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How many different arrangements of the letters in the word SCHOOL are there?

pogonyaev

36; there are 6 letters in the word school so if you multiple it by 6 which is the amount of different places one letter could be, the result would be 36

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3 years ago

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Match solutions and differential equations. Note: Each equation may have more than one solution. Select all that apply. (a) 7y''

Nonamiya [84]

Answer:

a- $e^x,e^{-x}$

b- $x^{-2}$

c- $x^3$

Step-by-step explanation:

a.7 y''-7 y =0

Auxillary equation

$D^2-1=0$

$(D-1)(D+1)=0$

D=1,-1

Then , the solution of given differential equation

$y=e^x,y=e^{-x}$

2. $7x^2y''+14xy'-14 y=0$

Y= $y=x^3$

$y=3x^2$

$y''=6x$

Substitute in the given differential equation

$42x^3+42x^3-14x^3\neq 0$

Hence, $x^3$ is not a solution of given differential equation

$e^x,e^{-x}$ are also not a solution of given differential equation.

y= $x^{-2}$

$y'=-2x^{-3}$

$y''=6x^{-4}$

Substitute the values in the differential equation

$7x^2(6x^{-4})+14x(-2x^{-3})-14 x^{-2}$

= $42x^{-2}-28x^{-2}-14x^{-2}=0$

Hence, $x^{-2}$ is a solution of given differential equation.

c. $7x^2y''-42y=0$

$y=x^3$

$y'=3x^2$

$y''=6x$

Substitute the values in the differential equation

$42x^3-42x^3=0$

Hence, $x^3$ is a solution of given differential equation.

a- $e^x,e^{-x}$

b- $x^{-2}$

c- $x^3$

6 0

3 years ago

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Find the solution of this system of equations.

Evgesh-ka [11]

Answer:

Step-by-step explanation:

x + 2y = 8

x - y = 2

x + 2y = 8

-x + y = -2

3y = 6

y = 2

x - 2 = 2

x = 4

(4, 2)

8 0

2 years ago

Ivan will rent a car for the weekend. He can choose one of two plans. The first plan has no initial fee, but costs $0.90 per mil

borishaifa [10]

Answer:

$337.50

Step-by-step explanation:

The computation of the number of miles need to drive for determining the same cost is given below:

Let us assume the miles be x

So for the first plan, the equation is

= $0.90x

And for the second plan, the equation is

= $75 + $0.70x

Now equate this

0.90x = $75 + 0.70x

0.90x - 0.70x = $75

0.20x = $75

x = $75 ÷ 0.20

= 375 miles

Now the same cost would be

For plan A and plan B

0.90x = $75 + 0.70x

0.90(375) = $75 + 0.70(375)

$337.5 = $75 + $262.50

$337.50 = $337.50

7 0

2 years ago

2 please help. i will give brainlies and 50 points. if you use my points without an answer i will have your account deleted and

Iteru [2.4K]

Answer: Area: 5808 Primiter: 308

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3 years ago

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