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3 years ago

MARKING AS BRAINLIEST PLUS MANY POINTS

Mathematics

2 answers:

yulyashka [42]3 years ago

7 0

This is easy
since there’s no examples on the sides that’s okay the one that has a 2 on is a good starter bc u see all of the sides and almost the same but the top and bottom aren’t so we know that the left and right are 2x let’s figure out what the top and bottom are
2x2x2x2=16
so it’s 16

marshall27 [118]3 years ago

5 0

Answer:

2x little 2on top

Step-by-step explanation:

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I need help you guys

irakobra [83]

The answer would be 30

8 0

3 years ago

Read 2 more answers

HELP!! PLEASE!!! THANK YOU!!

Blizzard [7]

Answer:

C. 8x - 3y = 5

Step-by-step explanation:

7 - 3(x - y) = 5x + 2

Standard form: Ax + By = C

7 -3x + 3y = 5x + 2

7 -8x + 3y = 2

-8x + 3y = -5

Divide by -1 to each number

8x - 3y = 5

6 0

3 years ago

Rewrite in simplest radical form 1/x^-3/6

VladimirAG [237]

$\bf a^{\frac{{ n}}{{ m}}} \implies \sqrt[{ m}]{a^{ n}} \qquad \qquad

\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}
\\\quad \\
% rational negative exponent
a^{-\frac{{ n}}{{ m}}} =
 \cfrac{1}{a^{\frac{{ n}}{{ m}}}} \implies \cfrac{1}{\sqrt[{ m}]{a^{ n}}}
\\ \quad \\ \quad \\

% radical denominator
\cfrac{1}{\sqrt[{ m}]{a^{ n}}}= \cfrac{1}{a^{\frac{{ n}}{{ m}}}}\implies a^{-\frac{{ n}}{{ m}}}\qquad thus\\
----------------------------\\

\\ \quad \\

$ $\bf 
\\ \quad \\

\cfrac{1}{x^{-\frac{3}{6}}}\implies \cfrac{1}{x^{-\frac{1}{2}}}\implies \cfrac{1}{\frac{1}{x\frac{1}{2}}}\implies \cfrac{1}{1}\cdot \cfrac{x^{\frac{1}{2}}}{1}
\\ \quad \\
x^{\frac{1}{2}}\implies \sqrt{x}$

4 0

4 years ago

Please help!! You will recieve 25 points if you answer correctly!

s344n2d4d5 [400]

When the graph rises one square for a run of one square, the slope is 2 km/(0.5 h) = 4 km/h. When the graph rises half that fast, the slope is 2 km/h. When the graph is horizontal, the slope is 0. The slope of the distance vs time curve is the speed.

S = 4 km/h, when 0 < t < 2 h
S = 0, when 2 h ≤ t < 2.5 h
S = 4 km/h, when 2.5 h ≤ t < 3 h
S = 0, when 3h ≤ t < 4 h
S = 2 km/h, when 4 h ≤ t < 5 h

8 0

4 years ago

The lower supports are and the area of the two supports is square meters. The upper arch can be decomposed as one semicircle wit

Galina-37 [17]

Answer:

The lower supports are Congruent Rectangles and the area of the two supports is 24 square meters.

The upper arch can be decomposed as one semicircle with radius 6 meters minus a semicircle with radius 3 meters.

The area of the archway is (13.5 π + 24) square meters.

Step-by-step explanation:

See attachment for the firgure,

In order to determine the area of archway = The area of upper support + area of lower support.

As given, the lower support are two congruent rectangles consists of dimension 3 m × 4 m

Therefore, the area of lower support can be written as,

The area of lower support = 3 × 4 + 3 × 4 = 12 + 12 = 24 square m.

Now, the upper support arch can be decomposed as the two concentric semi circles having radius 3 m and 6 m,

Hence, the area of the upper support = Area of semi circle having radius i.e 6 m - Area of semi circle having radius i.e 3 m

=> π6²/2 - π3²/2= 27π/2= 13.5π square m

Therefore, the area of the archway = (13.5 π + 24) square meters

4 0

4 years ago