Sometimes, it is hard to see which function fits g(x). We are given the point (4,1). Luckily, the point lies on g(x). We can plug in (4,1) into the g(x) equations and see which best fits.

A. Incorrect

$1=4(4)^2$

$1=4(16)$

$1\neq 64$

B. Incorrect

$1=\frac{1}{4} (4)^2$

$1=\frac{1}{4} (16)$

$1\neq 4$

C. Incorrect

$1=(\frac{1}{2}(4))^2$

$1=(2)^2$

$1\neq 4$

D. Correct

$1=(\frac{1}{4}(4))^2$

$1=(1)^2$

$1=1$

4 0

3 years ago

Point Mis the midpoint of AB. AM = 3x + 3, and AB= 83 – 6.

Ber [7]

Answer:

AM= Half of AB

or, 3x+3=(8x-6)/2

or, 6x+6=8x-6

or, 2x=12

Therefore,x=6

so,AM=3*6+3=21

So the units is 21

4 0

3 years ago

Read 2 more answers

A line segment whose endpoints are (2,6) and (8,y) is perpendicular to a line whose slope is -4. What is the value of y?

Mariulka [41]

If the line segment is perpendicular to a line with the slope of -4, that means the line segment has a slope of 1/4.

First let's make an equation for the line segment using the slope of 1/4 and the point at (2,6) to find the final piece, the y-intercept

y = mx + b
6 = 1/4(2) + b
6 = 2/4 + b
24/4 = 2/4 + b
22/4 = b

y = 1/4 x + 22/4
6 = 1/4(2) + 22/4
6 = 2/4 + 22/4
6 = 24/4
6 = 6 <-- proves that this equation is correct

Now you may plug in the x to find y. ( 8 , y )
y = 1/4(8) + 22/4
y = 8/4 + 22/4
y = 30/4 = 15/2 = 7.5

4 0

3 years ago