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3 years ago

14

What is the answer to g + 6t

2 answers:

Lisa [10]3 years ago

8 0

Answer:

g6t

Step-by-step explanation:

liq [111]3 years ago

5 0

whattt? I think that's wrong

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Write the slope-intercept form of the equation for the line.

lesya692 [45]

Answer: y=2x-1

Explanation:

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3 years ago

You deposit $ 4000 into an account paying 6 % annual interest compounded quarterly. How much money will be in the account after

Semmy [17]

Answer:

$1200

Step-by-step explanation:

You start with your equation of 5x +.06 =4000 . 6% of 4000 is 240. times 240 by 5 and you get your answer of 1200 dollars.

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3 years ago

Read 2 more answers

zlopas [31]

Answer:

<h2>13</h2>

Step-by-step explanation:

24, 10 and 26

It's te Pythagorean triple:

$10$

Therefore, te given triangle is a right triangle.

A radius of the circumscribed circle is equal a half hypotenuse length.

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3 years ago

Evaluate 2/3 + 1/3 + 1/6 + … THIS IS CONTINUOUS. It is NOT as simple as 2/3 + 1/3 + 1/6.

Vlada [557]

$a=\dfrac{2}{3}\\r=\dfrac{1}{2}$

The sum exists if $|r|$

$\left|\dfrac{1}{2}\right|$ therefore the sum exists

$\displaystyle\\\sum_{k=0}^{\infty}ar^k=\dfrac{a}{1-r}$

$\dfrac{2}{3}+\dfrac{1}{3}+\dfrac{1}{6}+\ldots=\dfrac{\dfrac{2}{3}}{1-\dfrac{1}{2}}=\dfrac{\dfrac{2}{3}}{\dfrac{1}{2}}=\dfrac{2}{3}\cdot 2=\dfrac{4}{3}$

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3 years ago

What is the solution of x^2+x-6/x-7<0 PLEASE HELP ME :( (it’s not the 2nd one i already tried it)

blsea [12.9K]

Answer:

the first one $\:x\le \:-3\quad \mathrm{or}\quad \:2\le \:x$

Step-by-step explanation:

Factor $x^2+x-6$ :

Break the expression into groups

$\left(x^2-2x\right)+\left(3x-6\right)$

$\mathrm{Factor\:out\:}x\mathrm{\:from\:}x^2-2x\mathrm{:\quad}$

$x\left(x-2\right)$

$\mathrm{Factor\:out\:}3\mathrm{\:from\:}3x-6\mathrm{:\quad}$

$3\left(x-2\right)$

$x\left(x-2\right)+3\left(x-2\right)$

$\mathrm{Factor\:out\:common\:term\:}x-2$

$\left(x-2\right)\left(x+3\right)$

$\frac{\left(x-2\right)\left(x+3\right)}{x-7}\\$

$\frac{\left(x-2\right)\left(x+3\right)}{x-7}\le \:0$

$\mathrm{Find\:the\:signs\:of\:the\:factors\:of\:}\frac{\left(x-2\right)\left(x+3\right)}{x-7}$

$\mathrm{Identify\:the\:intervals\:that\:satisfy\:the\:required\:condition:}\:\le \:\:0$

$x$

Merge Overlapping Intervals

$x\le \:-3\quad \mathrm{or}\quad \:2\le \:x$

6 0

3 years ago