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2 years ago

What is the slope of the line?

Mathematics

1 answer:

Lapatulllka [165]2 years ago

8 0

Answer:

$m=\frac{2}{3}$

Step-by-step explanation:

We can see that some of the points that are plotted we can tell what those plots are (-2, 0) (1, 2) (4, 4)

We use the slope formula $m=\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$ for any of the two plots that are shown on the line

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Which expression is not equivalent to Negative 3 x minus one-half 4 y? 2 y minus 5 x minus one-half 2 y 2 x Negative 2 x minus o

Alona [7]

Answer:

The wrt=itten expressions are too difficult to interpret properly. I did my best but I don't see any of the answers as equivalent to -3x - 2y, so please check my interpretations of the answer options.

Step-by-step explanation:

"Negative 3 x minus one-half 4 y"

-3x- (1/2)4y

or -3x - 2y

=====

The answer options are too garbled for me to make sense of them. Are they:

1. 2 y minus 5 x minus one-half 2 y : 2y -5x - (1/2)2y; y -5x ?

2. 2 x Negative 2 x minus one-half 6 y : 2(-2x)- (1/2)6y; -4x - 3y ?

3. 3 x Negative 3 x minus three-fourths 4 y : 3x(-3x) - (3/4)4y; -9x -3y ?

4. one-fourth Negative 3 y minus three-fourths 7 y one-fourth minus 3 x:

(1/4)(-3y) - (3/4)7y - (1/4)(-3x); -(3/4)y -(21/4)y + (3/4)x; -(24/4)y + (3/4)x; ?

I don't see any of the answers as equivalent to -3x - 2y, so please check my interpretations of the answer options.

8 0

2 years ago

Read 2 more answers

Suppose an opaque jar contains 3 red marbles and 10 green marbles. The following exercise refers to the experiment of picking tw

kow [346]

Answer:

$\frac{5}{13}$

Step-by-step explanation:

Given,

Red marbles = 3,

Green marbles = 10,

So, the total marbles = 3 + 10 = 13,

$\because \text{Probability}=\frac{\text{Favourable outcomes}}{\text{Total outcomes}}$

Since, here replacement is not allowed,

Thus, the probability of getting a green marble and a red marble

= first red and second green + first green second red

$=\frac{3}{13}\times \frac{10}{12}+\frac{10}{13}\times \frac{3}{12}$

$=2\times \frac{3}{13}\times \frac{10}{12}$

$=\frac{30}{78}$

$=\frac{5}{13}$

Note : The probability of getting a green marble first and a red marble second

= $\frac{10}{13}\times \frac{3}{12}$

$=\frac{30}{156}$

$=\frac{5}{26}$

4 0

3 years ago

Suppose that W1, W2, and W3 are independent uniform random variables with the following distributions: Wi ~ Uni(0,10*i). What is

nadya68 [22]

I'll leave the computation via R to you. The $W_i$ are distributed uniformly on the intervals $[0,10i]$ , so that

$f_{W_i}(w)=\begin{cases}\dfrac1{10i}&\text{for }0\le w\le10i\\\\0&\text{otherwise}\end{cases}$

each with mean/expectation

$E[W_i]=\displaystyle\int_{-\infty}^\infty wf_{W_i}(w)\,\mathrm dw=\int_0^{10i}\frac w{10i}\,\mathrm dw=5i$

and variance

$\mathrm{Var}[W_i]=E[(W_i-E[W_i])^2]=E[{W_i}^2]-E[W_i]^2$

We have

$E[{W_i}^2]=\displaystyle\int_{-\infty}^\infty w^2f_{W_i}(w)\,\mathrm dw=\int_0^{10i}\frac{w^2}{10i}\,\mathrm dw=\frac{100i^2}3$

so that

$\mathrm{Var}[W_i]=\dfrac{25i^2}3$

Now,

$E[W_1+W_2+W_3]=E[W_1]+E[W_2]+E[W_3]=5+10+15=30$

and

$\mathrm{Var}[W_1+W_2+W_3]=E\left[\big((W_1+W_2+W_3)-E[W_1+W_2+W_3]\big)^2\right]$

$\mathrm{Var}[W_1+W_2+W_3]=E[(W_1+W_2+W_3)^2]-E[W_1+W_2+W_3]^2$

We have

$(W_1+W_2+W_3)^2={W_1}^2+{W_2}^2+{W_3}^2+2(W_1W_2+W_1W_3+W_2W_3)$

$E[(W_1+W_2+W_3)^2]$

$=E[{W_1}^2]+E[{W_2}^2]+E[{W_3}^2]+2(E[W_1]E[W_2]+E[W_1]E[W_3]+E[W_2]E[W_3])$

because $W_i$ and $W_j$ are independent when $i\neq j$ , and so

$E[(W_1+W_2+W_3)^2]=\dfrac{100}3+\dfrac{400}3+300+2(50+75+150)=\dfrac{3050}3$

giving a variance of

$\mathrm{Var}[W_1+W_2+W_3]=\dfrac{3050}3-30^2=\dfrac{350}3$

and so the standard deviation is $\sqrt{\dfrac{350}3}\approx\boxed{116.67}$

# # #

A faster way, assuming you know the variance of a linear combination of independent random variables, is to compute

$\mathrm{Var}[W_1+W_2+W_3]$

$=\mathrm{Var}[W_1]+\mathrm{Var}[W_2]+\mathrm{Var}[W_3]+2(\mathrm{Cov}[W_1,W_2]+\mathrm{Cov}[W_1,W_3]+\mathrm{Cov}[W_2,W_3])$

and since the $W_i$ are independent, each covariance is 0. Then

$\mathrm{Var}[W_1+W_2+W_3]=\mathrm{Var}[W_1]+\mathrm{Var}[W_2]+\mathrm{Var}[W_3]$

$\mathrm{Var}[W_1+W_2+W_3]=\dfrac{25}3+\dfrac{100}3+75=\dfrac{350}3$

and take the square root to get the standard deviation.

8 0

3 years ago

How could the relationship of the data be classified? (1 point) a fairly strong positive correlation a fairly weak positive corr

sladkih [1.3K]

Where's the data lol

3 0

3 years ago

Simplify x + 1/2 (x-5) =20

Aneli [31]

Answer: x=15

Step-by-step explanation: Let's solve your equation step-by-step.

x+ 1 /2

(x−5)=20

Step 1: Simplify both sides of the equation.

x+ 1 /2

(x−5)=20

x+( 1 /2 )(x)+( 1 /2 )(−5)=20(Distribute)

x+ 1 /2

x+ −5 /2 =20

(x+ 1 /2 x)+( −5 /2 )=20(Combine Like Terms)

3 /2 x + −5 /2 =20

Step 2: Add 5/2 to both sides.

3 /2 x + −5 /2 + 5 /2 =20+ 5 /2

3 /2 x= 45 /2

Step 3: Multiply both sides by 2/3.

( 2 /3 )*( 3 /2 x)=( 2 /3 )*( 45 /2 )

x=15

5 0

3 years ago

What is the slope of the line?​

What is the slope of the line?