m<E=45.5 m<F=45.5
this is question 8 can't see question 9
Answer:
length = 30 cm
Breadth = 10 cm
Step-by-step explanation:
Length = x cm
Breadth = (1/3)x
Perimeter = 80 cm
2(length + breadth) = 80
2* (x + (1/3)x) = 80
x = 30cm
length = 30 cm
breadth = 
cm
We want double sixes. This means that we want both the first roll and the second roll to be 6.
The given point is given as (r1 , r2) where:
r1 is output from first roll
r2 is output from second roll
Since we want both outputs to be 6, therefore, the answer would be: (6,6)
Answer:
6
Step-by-step explanation:
4x-12 = x+7
4x-12+12 = x+7+12
4x = x+19
4x-x = x+19-x
3x=19
x = 6
And if we substitute the value of x into the equation 4x-12 = x+7,
we will get 13 = 13 in the end.
Hope this helps :)
LHS ⇒ RHS:
Identities:
[1] cos(2A) = 2cos²(A) - 1 = 1 - 2sin²(A)
[2] sin(2A) = 2sin(A)cos(A)
[3] sin(A + B) = sin(A)cos(B) + cos(A)sin(B)
[4] cos(A + B) = cos(A)cos(B) - sin(A)sin(B)
cos(x) - cos(x + 2Θ)
= cos(x) - (cos(x)cos(2Θ) - sin(x)sin(2Θ)) [4]
= cos(x) - cos(x)(1 - 2sin²(Θ)) + sin(x)(2sin(Θ)cos(Θ)) [1] [2]
= cos(x) - cos(x) + 2sin²(Θ)cos(x) + 2sin(Θ)sin(x)cos(Θ)
= 2sin²(Θ)cos(x) + 2sin(Θ)sin(x)cos(Θ)
= 2sin(Θ)(sin(Θ)cos(x) + sin(x)cos(Θ))
= 2sin(Θ)sin(x + Θ)
