F(x) = 2x - 4
f(2 ≤ x) = 2(2 ≤ x) - 4
f(x ≥ 2) = 2(x ≥ 2) - 4
f(x ≥ 2) = 2(x) ≥ 2(2) - 4
f(x ≥ 2) = 2x ≥ 4 - 4
f(x ≥ 2) = 2x ≥ 0
f(x ≥ 2) = x ≥ 0
f(x) = 2x - 4
f(x ≤ 6) = 2(x ≤ 6) - 4
f(x ≤ 6) = 2(x) ≤ 2(6) - 4
f(x ≤ 6) = 2x ≤ 12 - 4
f(x ≤ 6) = 2x ≤ 8
f(x ≤ 6) = x ≤ 4
First factor -12m^n - 49mn - 44n^2 to get -(4n+3m)(11n + 4m) then the equation would be:
-(3m + 4n)(4m + 11n) / (-3m - 4n)
Then, cancel out the like terms and the final answer would be
4m + 11n
So, when adding in the 7 and 3 the new equation is:
9{(9x7)+(4x3)+9}
Following pemdas, you have to do parenthesis first. So now the equation is:
9(63+12+9)
Now distribute the 9:
567 + 108 + 81
And finally solve as a normal addition problem:
567 + 108 + 81= 756
So, the answer is 756.
I hope this helps:)
Answer:
Step-by-step explanation:
This is a binomial probability distribution because there are only 2 possible outcomes. It is either a randomly selected student grabs a packet before being seated or the student sits first before grabbing a packet. The probability of success, p in this scenario would be that a randomly selected student sits first before grabbing a packet. Therefore,
p = 1 - 0.81 = 0.91
n = 9 students
x = number of success = 3
The probability that exactly two students sit first before grabbing a packet, P(x = 2) would be determined from the binomial probability distribution calculator. Therefore,
P(x = 2) = 0.297
First, find 3/4 of 24. 24/4=6, 6x3= 18. Now, find 1/9 of 18. 18 divided by the denominator, 9, is 2. Since the numerator is one, our answer remains as 2. So yeah, the answer is 2.