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ludmilkaskok [199]
3 years ago
14

Consider the sequence of numbers 3/8,3/4, 1 1/8,1 7/8 Which statement is a description of the sequence?

Mathematics
2 answers:
allochka39001 [22]3 years ago
8 0

Answer:The sequence is recursive and can be represented by the function f(n+1)=f(n)+3/8

Step-by-step explanation:

adoni [48]3 years ago
6 0
The complete question in the attached figure

Let
for n=1
f(1)=3/8

for n=2
f(2)=3/4

for n=3
f(3)=1 1/8

for n=4
f(4)=1 1/2

for n=5
f(5)=1 7/8

we know that
f(2)-f(1)=3/4-3/8=3/8------> f(2)=f(1)+3/8

f(3)-f(2)=1 1/8-3/4----> 9/8-6/8----> 3/8-----> f(3)=f(2)+3/8

f(4)-f(3)=1 1/2-1 1/8-----> 12/8-9/8----> 3/8-----> f(4)=f(3)+3/8

f(5)-f(4)=1 7/8-1 1/2-----> 15/8-12/8---> 3/8-----> f(5)=f(4)+3/8

therefore

the answer is the option
The sequence is recursive and can be represented by the function f(n + 1) = f(n) + 3/8 

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4- A manufacturing process produces items whose weights are normally distributed. It is known that 22.57% of all the items produ
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Answer:

\\ \mu = 118\;grams\;and\;\sigma=30\;grams

Step-by-step explanation:

We need to use z-scores and a standard normal table to find the values that corresponds to the probabilities given, and then to solve a system of equations to find \\ \mu\;and\;\sigma.

<h3>First Case: items from 100 grams to the mean</h3>

For finding probabilities that corresponds to z-scores, we are going to use here a <u>Standard Normal Table </u><u><em>for cumulative probabilities from the mean </em></u><em>(Standard normal table. Cumulative from the mean (0 to Z), 2020, in Wikipedia) </em>that is, the "probability that a statistic is between 0 (the mean) and Z".

A value of a z-score for the probability P(100<x<mean) = 22.57% = 0.2257 corresponds to a value of z-score = 0.6, that is, the value is 0.6 standard deviations from the mean. Since this value is <em>below the mean</em> ("the items produced weigh between 100 grams up to the mean"), then the z-score is negative.

Then

\\ z = -0.6\;and\;z = \frac{x-\mu}{\sigma}

\\ -0.6 = \frac{100-\mu}{\sigma} (1)

<h3>Second Case: items from the mean up to 190 grams</h3>

We can apply the same procedure as before. A value of a z-score for the probability P(mean<x<190) = 49.18% = 0.4918 corresponds to a value of z-score = 2.4, which is positive since it is after the mean.

Then

\\ z =2.4\;and\; z = \frac{x-\mu}{\sigma}

\\ 2.4 = \frac{190-\mu}{\sigma} (2)

<h3>Solving a system of equations for values of the mean and standard deviation</h3>

Having equations (1) and (2), we can form a system of two equations and two unknowns values:

\\ -0.6 = \frac{100-\mu}{\sigma} (1)

\\ 2.4 = \frac{190-\mu}{\sigma} (2)

Rearranging these two equations:

\\ -0.6*\sigma = 100-\mu (1)

\\ 2.4*\sigma = 190-\mu (2)

To solve this system of equations, we can multiply (1) by -1, and them sum the two resulting equation:

\\ 0.6*\sigma = -100+\mu (1)

\\ 2.4*\sigma = 190-\mu (2)

Summing both equations, we obtain the following equation:

\\ 3.0*\sigma = 90

Then

\\ \sigma = \frac{90}{3.0} = 30

To find the value of the mean, we need to substitute the value obtained for the standard deviation in equation (2):

\\ 2.4*30 = 190-\mu (2)

\\ 2.4*30 - 190 = -\mu

\\ -2.4*30 + 190 = \mu

\\ \mu = 118

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